作者热门文章
- iOS/Objective-C 元类和类别
- objective-c - -1001 错误,当 NSURLSession 通过 httpproxy 和/etc/hosts
- java - 使用网络类获取 url 地址
- ios - 推送通知中不播放声音
我是 Servlet 功能的新手。我试图在 JSP 表单中获取一些数据并尝试使用 Servlet 在控制台中打印它。但我无法做到这一点。
web.xml
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<servlet>
<servlet-name>controlServlet</servlet-name>
<servlet-class>com.selenium8x8.servlet.ControlServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>controlServlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
启动.jsp
<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<form action="Startup" method="post">
<input type="text" name="name"/><br>
<input type="text" name="group"/>
<input type="text" name="pass"/>
<input type="submit" value="submit">
</form>
</body>
</html>
ControlServlet.java
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class ControlServlet extends HttpServlet {
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String name = request.getParameter("name");
String group = request.getParameter("group");
String pass = request.getParameter("pass");
System.out.println("Name :"+ name);
System.out.println("group :"+ group);
System.out.println("pass :"+ pass);
}
}
执行后报如下错误
HTTP Status 405 - HTTP method GET is not supported by this URL
type Status report
message HTTP method GET is not supported by this URL
description The specified HTTP method is not allowed for the requested resource.
最佳答案
@Prassana:请如下修改您的 web.xml,它应该可以工作。我测试了您的代码及其对我的工作。这对 GET 和 POST 都有效。
<servlet>
<servlet-name>ControlServlet</servlet-name>
<servlet-class>com.selenium8x8.servlet.ControlServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ControlServlet</servlet-name>
<url-pattern>/Startup</url-pattern>
</servlet-mapping>
</web-app>
关于java - 如何从JSP页面获取数据到servlet,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19405757/
我是一名优秀的程序员,十分优秀!