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java - 使用 "for"循环在 java 中打印出菱形图案

转载 作者:塔克拉玛干 更新时间:2023-11-02 08:40:57 25 4
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我很难用 Java 完成学校练习。我们被要求打印出这个图案:

+++++++++++++++++++++++++++++++++++++++++++++
+++++++ +++++++ +++++++ +++++++ +++++++
+++++ +++++ +++++ +++++ +++++
+++ +++ +++ +++ +++
+ + + + +
+++ +++ +++ +++ +++
+++++ +++++ +++++ +++++ +++++
+++++++ +++++++ +++++++ +++++++ +++++++
+++++++++++++++++++++++++++++++++++++++++++++
+++++++ +++++++ +++++++ +++++++ +++++++
+++++ +++++ +++++ +++++ +++++
+++ +++ +++ +++ +++
+ + + + +
+++ +++ +++ +++ +++
+++++ +++++ +++++ +++++ +++++
+++++++ +++++++ +++++++ +++++++ +++++++
+++++++++++++++++++++++++++++++++++++++++++++
+++++++ +++++++ +++++++ +++++++ +++++++
+++++ +++++ +++++ +++++ +++++
+++ +++ +++ +++ +++
+ + + + +
+++ +++ +++ +++ +++
+++++ +++++ +++++ +++++ +++++
+++++++ +++++++ +++++++ +++++++ +++++++
+++++++++++++++++++++++++++++++++++++++++++++

我可以做三角形或沙漏形状,但我无法让它水平重复。

这是我目前所拥有的:

int a = 9;
char b = '+';
char c = ' ';

int i_buffer = a;
int i_leer = 1;
for (int i = 0; i < a; i++) {
for (int z = i_buffer; z > 0; z--)
System.out.print(b);

System.out.println();

i_buffer = i_buffer - 2;
if (i_buffer < 0)
break;

for (int z = i_leer++; z > 0; z--)
System.out.print(c);
}

最佳答案

这是一个解决方案,可以根据需要在 x 和 y 维度上为每个尺寸创建此图案。实际发生的情况被写为评论。

public static void main(String[] args) {
test();
}

public static void test() {
// Print it three times under each other, 5 times next to each other
// With a size of 9 plus
printHourglass(3,5,9);
}

private static void printHourglass(int column, int times, int size) {
for(int i = 0;i<column;++i) {
// If it is the first iteration print the first line, otherwhise
// Leave out the first only plus line
printHourglassRow(times, size, i == 0 ? 0 : 1);
}
}

private static void printHourglassRow(int times, int size, int start) {
// If it is not the first hourglass don´t print the first only plus row
int printableStars = start == 0 ? size : size-2;
int printableSpaces = start == 0 ? 0 : 1;
// If the size is even we need to print one row less
size = size % 2 == 0 ? size-1:size;
for(int i = start;i<size;++i) {
// Decides if we should print whitespaces or spaces first.
// only The first and last row start with the plus
int mode = (i == size || i == 0) ? 1 : 0;
//System.out.println(mode);
//System.out.println(printableStars);
// We are printing each column, we start with column 0
int column = 0;
// We print until we did reach the last column.
while(column<times*size) {
// If we are in print plus mode the next thing we print
// will be a space, so switch mode and print stars as long as we should
if(mode == 1) {
mode = 0;
for(int j = 0;j<printableStars;++j) {
printPlus();
++column;
}
// If we are in print whitespace mode the next thing we print
// will be a space, so switch mode and print whitespaces as long as we should
} else {
mode = 1;
// If we reached the second hourglass (column > size/2)
// Then we need to print twice as much whitespaces
int sizeHalf = size % 2 == 0? size/2 : size/2+1;
for(int j = 0;column > sizeHalf ? j<printableSpaces*2:j<printableSpaces;++j) {
printSpace();
++column;
}
}
}
// We are not in the middle of the hourglass so
// We print two stars less and one whitespace more.
if(size - 2*i > 2) {
++printableSpaces;
printableStars -= 2;
// If we are reaching the point where we are in the middle
// Of the houreglass we need to print one whitespace less
// and two plus more.
} else {
--printableSpaces;
printableStars += 2;
}
// Linebreak
System.out.println();
}
}

private static void printPlus() {
System.out.print("+");
}

private static void printSpace() {
System.out.print(" ");
}

关于java - 使用 "for"循环在 java 中打印出菱形图案,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33545825/

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