java - 使用正则表达式匹配文本行

Question

我有这样的行:

36600.10: [Host #255] utilization is 0.00%
36600.10: [Host #256] utilization is 21.64%
36600.10: [Host #257] utilization is 3.29%
36600.10: [Host #258] utilization is 0.94%
36600.10: [Host #260] utilization is 3.76%
36600.10: [Host #260] utilization is 1.21%
36600.10: [Host #260] utilization is 86.09%
36600.10: [Host #260] utilization is 7.32%

我需要在 utilization is 之后获取所有数字。我想要的是这样的数组:

myArray[0] => 0.00,
myArray[1] => 21.64,
myArray[2] => 3.29,
myArray[3] => 0.94,
myArray[4] => 3.76,
myArray[5] => 1.21,
myArray[6] => 7.32

到目前为止我尝试了什么(它只适用于第一行):

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class main {

    public static void main(String[] args) {
          String lines = "36600.10: [Host #256] utilization is 21.65% \n 36600.10: [Host #256] utilization is 91.78% \n 36600.10: [Host #256] utilization is 3.29%";
          String pattern = "(utilization is\\s)(\\d+\\.\\d*)(.*)";

          Pattern r = Pattern.compile(pattern);

          Matcher m = r.matcher(lines);
          if (m.find( )) {
             System.out.println(m.group(2));
          } else {
             System.out.println("NO MATCH");
          }

    }

}

抱歉，我是 Java 的新手，尝试了一些模式但没有帮助。任何帮助将不胜感激。

Answer 1

使用 While 循环。 If 语句将限制与第一次出现的匹配(正在​​发生)

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class main {

    public static void main(String[] args) {
          String lines = "36600.10: [Host #256] utilization is 21.65% \n 36600.10: [Host #256] utilization is 91.78% \n 36600.10: [Host #256] utilization is 3.29%";
          String pattern = "(utilization is\\s)(\\d+\\.\\d*)(.*)";

          Pattern r = Pattern.compile(pattern);

          Matcher m = r.matcher(lines);
         while (m.find()) {
             System.out.println(m.group(2));
          } 
    }

}