java - 如何使用 Waffle 获取客户端用户名？

Question

我在 Windows 7 上运行 Tomcat 7。所有客户端也都运行 Windows 7。

我试图在 test.jsp 页面上打印客户端用户名，所以我使用 Waffle 。这是 WEB-INF/web.xml

 <filter>
  <filter-name>SecurityFilter</filter-name>
  <filter-class>waffle.servlet.NegotiateSecurityFilter</filter-class>
  <init-param>
    <param-name>impersonate</param-name>
    <param-value>true</param-value>
  </init-param>
</filter> 

这是我的test.jsp

<% 
    String userId = Secur32Util.getUserNameEx(Secur32.EXTENDED_NAME_FORMAT.NameSamCompatible); 
    out.println(userId); 
%> 

但是它总是打印 server computer username 。我在许多 client 机器上试过，它总是打印 server 而不是 client userid

为什么？如何纠正这个？

Answer 1

首先，将 waffle-api.jar 放在您的项目类路径中。然后将此 xml 代码放在您的 web.xml 中。

<filter>
    <filter-name>SecurityFilter</filter-name>
    <filter-class>waffle.servlet.NegotiateSecurityFilter</filter-class>
    <init-param>
        <param-name>principalFormat</param-name>
        <param-value>fqn</param-value>
    </init-param>
    <init-param>
        <param-name>roleFormat</param-name>
        <param-value>both</param-value>
    </init-param>
    <init-param>
        <param-name>allowGuestLogin</param-name>
        <param-value>true</param-value>
    </init-param>
    <init-param>
        <param-name>securityFilterProviders</param-name>
        <param-value>
        waffle.servlet.spi.NegotiateSecurityFilterProvider
        waffle.servlet.spi.BasicSecurityFilterProvider
    </param-value>
    </init-param>
    <init-param>
        <param-name>waffle.servlet.spi.NegotiateSecurityFilterProvider/protocols</param-name>
        <param-value>
        Negotiate
        NTLM
    </param-value>
    </init-param>
    <init-param>
        <param-name>waffle.servlet.spi.BasicSecurityFilterProvider/realm</param-name>
        <param-value>WaffleFilterDemo</param-value>
    </init-param>
</filter>
<filter-mapping>
    <filter-name>SecurityFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

并使用下面的代码获取您的客户用户名；

HttpServletRequest request = (HttpServletRequest)Executions.getCurrent().getNativeRequest();
String user = request.getRemoteUser();

更多详情请访问:

https://github.com/dblock/waffle

归功于 klepon

资源链接:

1. http://forum.zkoss.org/question/96532/get-clients-username/
2. https://stackoverflow.com/a/5891022/2293534