gpt4 book ai didi

ios - 如何在ios中获取所有坐标点(X和Y)

转载 作者:塔克拉玛干 更新时间:2023-11-02 08:36:20 25 4
gpt4 key购买 nike

我正在编写一个应用程序,允许用户在 View 中绘制他们想要的任何内容。当他们绘图时,我使用 Json 将坐标值同时发送到 Web 并在 Web 中绘制相同的图表。当我慢慢画的时候,我得到了所有这样的坐标值。

{"XY":["92,240","94,240","96,240","97,240","98,240","99,240","100,240","102,240","103,240","104,240","104,240","105,240","106,240","107,240","108,240","108,240","110,240","110,240","112,240","112,240","114,240","115,240","116,240","117,240","118,240","120,240","120,240","120,240","122,240","122,240","124,240","124,240","126,240"]}

但是当我快速绘图时,我得到了想要的绘图但缺少很多坐标值。

{"XY":["96,320","117,302","170,262","252,208"]}

下面是我用来实现这个的代码。

@implementation PJRSignatureView
{
UIBezierPath *beizerPath;
UIImage *incrImage;
CGPoint points[10];
uint control;
}
- (void)drawRect:(CGRect)rect
{
[incrImage drawInRect:rect];
[beizerPath stroke];

// Set initial color for drawing

UIColor *fillColor = INITIAL_COLOR;
[fillColor setFill];
UIColor *strokeColor = INITIAL_COLOR;
[strokeColor setStroke];
[beizerPath stroke];

}

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
if ([lblSignature superview]){
[lblSignature removeFromSuperview];
}
rectArray = [[NSMutableArray alloc] init];
control = 0;
UITouch *touch = [touches anyObject];
points[0] = [touch locationInView:self];

CGPoint startPoint = points[0];
CGPoint endPoint = CGPointMake(startPoint.x + 1.5, startPoint.y
+ 2);



[beizerPath moveToPoint:startPoint];
NSLog(@"myPoint = %@", [NSValue valueWithCGPoint:endPoint]);
NSLog(@"beizerPath :%@",beizerPath);
[beizerPath addLineToPoint:endPoint];
NSLog(@"beizerPath end:%@",beizerPath);
}

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event
{
UITouch *touch = [touches anyObject];
CGPoint touchPoint = [touch locationInView:self];
control++;
points[control] = touchPoint;

if (control == 4)
{
points[3] = CGPointMake((points[2].x + points[4].x)/2.0, (points[2].y + points[4].y)/2.0);

[beizerPath moveToPoint:points[0]];
[beizerPath addCurveToPoint:points[3] controlPoint1:points[1] controlPoint2:points[2]];

[self setNeedsDisplay];

points[0] = points[3];
points[1] = points[4];
control = 1;
}
NSLog(@"beizerPathmove:%@",beizerPath);
NSString *rect_xy = [NSString stringWithFormat:@"%.f,%.f",touchPoint.x,touchPoint.y];

[rectArray addObject:rect_xy];
}

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{
[self drawBitmapImage];
[self setNeedsDisplay];
[beizerPath removeAllPoints];

NSMutableDictionary *rectDict = [[NSMutableDictionary alloc]init];
[rectDict setValue:rectArray forKey:@"XY"];
NSData *jsonData = [NSJSONSerialization dataWithJSONObject:rectDict options:0 error:nil];

// Checking the format
NSLog(@"%@",[[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding]);
control = 0;
}

如何在快速绘制时找到所有坐标值?

最佳答案

Apple 产品以特定的时间间隔发送触摸事件。因此,如果您缓慢地绘制/写入任何内容,则有可能获得所有坐标值,如果您快速绘制/写入,则会减少一些坐标值。并在您使用过的网络中应用相同类型的功能。希望现在能解决这个问题。

关于ios - 如何在ios中获取所有坐标点(X和Y),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30341143/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com