ios - Google iOS Geocoding SDK 反向经纬度到地点 ID

Question

目前，我们可以使用 GeoCoder 中的 reverseGeocodeCoordinate 将经纬度反转为地址。

https://developers.google.com/maps/documentation/ios/reference/interface_g_m_s_geocoder

但是，似乎没有办法将其逆向到Google places。

是否可以从iOS SDK获取地点？

谢谢亚历克斯

Answer 1

是的，您可以使用 iOS SDK 的 CLGeocoder。检查代码，

+ (void)fetchAddressFromCoordinates:(CoordinatesDataModel *)coordinates returnValue:(void(^)(NSString* address))returnBlock { 

CLLocation *currentLocation = [[CLLocation alloc] initWithLatitude:(CLLocationDegrees)[coordinateDataModel.latitude doubleValue]  longitude:(CLLocationDegrees)[coordinateDataModel.longitude doubleValue]];    
if (currentLocation != nil)  
// Reverse Geocoding
// “reverseGeocodeLocation” method to translate the locate data into a human-readable address.    
// The reason for using "completionHandler" ----
//  Instead of using delegate to provide feedback, the CLGeocoder uses “block” to deal with the response. By using block, you do not need to write a separate method. Just provide the code inline to execute after the geocoding call completes.
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error)
 {
     if (error == nil && [placemarks count] > 0)
     {
         if(placemarks && placemarks.count > 0)
         {
             CLPlacemark *placemark= [placemarks objectAtIndex:0];
             // address defined in .h file
             NSString *address = [NSString stringWithFormat:@"%@ %@ %@ %@ %@",[placemark subThoroughfare], [placemark thoroughfare], [placemark locality], [placemark administrativeArea], [placemark country]];

             NSCharacterSet *whitespace = [NSCharacterSet whitespaceCharacterSet];
             address = [address stringByTrimmingCharactersInSet:whitespace];

             NSMutableArray *words = [[address componentsSeparatedByCharactersInSet:whitespace] mutableCopy];
             //            NSLog(@":%@",words);
             NSMutableArray * wordsArray = [[NSMutableArray alloc] init];
             for (int i= 0; i< [words count]; i++) {
                 if (![[words objectAtIndex:i] isEqualToString:@"(null)"] ) {
                     [wordsArray addObject:[words objectAtIndex:i]];
                 }
             }
             address = [wordsArray componentsJoinedByString:@" "];
             returnBlock(address);
         }
     }
 }];}