java - JsonHttpResponseHandler - 方法不会覆盖其父类(super class)中的方法

Question

一段时间以来，我一直在为这段代码苦苦挣扎。为什么我会收到跟随错误？方法不会覆盖其父类(super class)中的方法这是代码:

public void CanSendPassword() {
    asyncHttpClientPassword = new AsyncHttpClient();
    requestParamsPassword = new RequestParams();

    requestParamsPassword.put("email", mEmail);
    asyncHttpClientPassword.post(BASE_URL, requestParamsPassword, new JsonHttpResponseHandler()
    {
        @Override
        public void onSuccess(int statusCode, Header[] headers, JSONObject response) {
            super.onSuccess(statusCode, headers, response);
            jsonResponse = response.toString();
        }

        @Override
        public void onFailure(int statusCode, Header[] headers, Throwable throwable, JSONObject errorResponse) {
            super.onFailure(statusCode, headers, throwable, errorResponse);
            jsonResponse = "failed";
        }
    }
    );
}

@override 都显示相同的错误并且 onSuccess 和 onFailure 也变灰了吗？

Answer 1

这是我的代码

TwitterRestClient

import android.content.Context;
import com.loopj.android.http.*;
import cz.msebera.android.httpclient.entity.StringEntity;

public class TwitterRestClient {
    private static final String BASE_URL = "https://www.example.com/api/";

    private static AsyncHttpClient client = new AsyncHttpClient();

    public static void get(String url, RequestParams params, AsyncHttpResponseHandler responseHandler) {
    client.get(getAbsoluteUrl(url), params, responseHandler);
    }

    public static void post(String url, RequestParams params, AsyncHttpResponseHandler responseHandler) {
    client.post(getAbsoluteUrl(url), params, responseHandler);
    }

    public static void post(Context ctx, String url, StringEntity entity, java.lang.String contentType, AsyncHttpResponseHandler responseHandler ){
    client.post(ctx,getAbsoluteUrl(url),entity,contentType,responseHandler);
    }

    private static String getAbsoluteUrl(String relativeUrl) {
        return BASE_URL + relativeUrl;
    }
}

这是我的 LoginAcitivity 中的方法

public void testPost(StringEntity entity) throws JSONException {
    TwitterRestClient.post(getApplicationContext(),"api-auth/", entity,"application/json", new JsonHttpResponseHandler() {

        @Override
        public void onSuccess(int statusCode, cz.msebera.android.httpclient.Header[] headers, org.json.JSONArray response) {
            // If the response is JSONObject instead of expected JSONArray
            GlobalFunctions.ShowToast(getApplicationContext(),"test");
        }

        @Override
        public void onFailure(int statusCode, cz.msebera.android.httpclient.Header[] headers, java.lang.Throwable throwable, org.json.JSONArray errorResponse){
            GlobalFunctions.ShowToast(getApplicationContext(),"test1123");
        }

        @Override
        public void onFailure(int statusCode, cz.msebera.android.httpclient.Header[] headers, java.lang.Throwable throwable, org.json.JSONObject errorResponse){
            GlobalFunctions.ShowToast(getApplicationContext(),errorResponse.toString());
        }

        @Override
        public void onFailure(int statusCode, cz.msebera.android.httpclient.Header[] headers, java.lang.String responseString, java.lang.Throwable throwable){
            GlobalFunctions.ShowToast(getApplicationContext(),responseString);
        }
    });
}

这是我在用户点击按钮时调用的内容

public void signIn(View v){
    try {

        String url = "/api-auth";

        JSONObject jsonParams = new JSONObject();

        jsonParams.put("username", "binsoi@gmail.com");
        jsonParams.put("password", "cornedbeef");

        StringEntity entity = new StringEntity(jsonParams.toString());
        client.post(context, url, entity, "application/json",
                responseHandler);

        testPost(entity);


    }  catch (Exception err)
    {
        GlobalFunctions.ShowToast(this, err.toString());
    }
}

希望这对您有所帮助，如果它不起作用请告诉我，因为我在发布前对其进行了编辑。