android - 设置 Android fragment 进入和退出转换？

Question

我正在尝试为 DialogFragment 设置进入和退出过渡，这看起来很简单。这是我的 DrinkDetailActivity 创建对话框的代码:

    fab.setOnClickListener(new View.OnClickListener(){
        @Override
        public void onClick(View v) {
            //create and display the dialog
            DialogFragment orderFragment = new OrderDrinkDialogFragment();

            //set the slide transition for the fragment
            Transition dialSlide = new Slide();
            dialSlide.setDuration(300);

            orderFragment.setEnterTransition(dialSlide);
            orderFragment.setExitTransition(dialSlide);
            orderFragment.show(getFragmentManager(), "order");
        }
    });

这是来 self 的 OrderDrinkDialogFragment 类的代码:

public class OrderDrinkDialogFragment extends DialogFragment
{
    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState)
    {
        AlertDialog.Builder builder = new AlertDialog.Builder(DrinkDetailActivity.activity);

        //set up the Linear Layout of the dialog
        LinearLayout layout = new LinearLayout(DrinkDetailActivity.activity);
        LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT,
                                                                     LinearLayout.LayoutParams.WRAP_CONTENT);
        layout.setOrientation(LinearLayout.VERTICAL);
        layout.setLayoutParams(params);

        //set up the EditText view
        EditText nameField = new EditText(DrinkDetailActivity.activity);
        nameField.setHint(R.string.dialog_name_hint);

        //add the EditText view to the layout
        layout.addView(nameField, new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT,
                                                            LinearLayout.LayoutParams.WRAP_CONTENT));

        //set layout as the view of the dialog
        builder.setView(layout);

        return builder.create();
    }
}

DrinkDetailActivity.activity 只是 DrinkDetailActivity 实例中的 this。出于某种原因，当我 show() 或关闭对话框时，对话框不会转换，它只是在 View 中弹出和弹出。 This教程对我确定应用程序其余部分的 Activity 转换有很大帮助，并且我遵循了与它所说的相同的 fragment 转换说明。我做错了什么？

Answer 1

这对我有用。我的向上滑动动画是

<?xml version="1.0" encoding="utf-8"?> <set xmlns:android="http://schemas.android.com/apk/res/android" >

    <translate
        android:duration="@android:integer/config_mediumAnimTime"
        android:fromYDelta="100%"
        android:interpolator="@android:anim/accelerate_interpolator"
        android:toXDelta="0" />

</set>

我的幻灯片动画是

<?xml version="1.0" encoding="utf-8"?>
<set xmlns:android="http://schemas.android.com/apk/res/android" >

    <translate
        android:duration="@android:integer/config_mediumAnimTime"
        android:fromYDelta="0%p"
        android:interpolator="@android:anim/accelerate_interpolator"
        android:toYDelta="100%p" />

</set>

在你的样式中添加这个

<style name="DialogAnimation">
    <item name="android:windowEnterAnimation">@anim/slide_up</item>
    <item name="android:windowExitAnimation">@anim/slide_down</item>
</style>

现在终于在 Dialog fragment 的 onCreateDialog() 中添加这个

public Dialog onCreateDialog(Bundle savedInstanceState) 
{
    final Dialog dialog = super.onCreateDialog(savedInstanceState);
    dialog.getWindow().getAttributes().windowAnimations = R.style.DialogAnimation;
    return dialog;
}