android - 当代码为401时如何在okhttp中获取响应体？

Question

我正在使用 OkHttp 3.2.0，这里是构建请求对象的代码:

MediaType JSON = MediaType.parse(AppConstants.CONTENT_TYPE_VALUE_JSON);
RequestBody body = RequestBody.create(JSON, requestBody);


    HttpUrl url = new HttpUrl.Builder()
                                    .scheme("http")
                                    .host("192.168.0.104")
                                    .port(8080)
                                    .addPathSegment("mutterfly-server")
                                    .addPathSegment("j_spring_security_check")
                                    .addQueryParameter("j_username", jsonObject.getString("emailId"))
                                    .addQueryParameter("j_password", jsonObject.getString("password"))
                                    .build();
        
     request = new Request.Builder()
                                    .addHeader(AppConstants.CONTENT_TYPE_LABEL, AppConstants.CONTENT_TYPE_VALUE_JSON)
                                    .addHeader(AppConstants.ACCEPT_LABEL, AppConstants.CONTENT_TYPE_VALUE_JSON)
                                    .url(url)
                                    .post(body)
                                    .build();

这是我解析响应的方式:

client.newCall(request).enqueue(new Callback() {
                @Override
                public void onFailure(Call call, IOException e) {
   
                }

                @Override
                public void onResponse(Call call, final Response response) throws IOException {

                    String respBody;
                    if (response.isSuccessful()) {
                        if (response.body() != null) {
                            respBody = response.body().string();
                            Log.i(TAG, respBody);
                            response.body().close();
                            if (AppMethods.checkIfNull(loginParserListener)) {
                                try {
                                    final VUser user = AppMethods.getGsonInstance().fromJson(respBody, VUser.class);
                                } catch (Exception e) {
  
                                }
                            }
                        }
                    } else {
                        
                        switch (response.code()){
                            case 401:
                                String body="HTTP_UNAUTHORIZED";
                                break;
                        }
                    }
                }
            });

这是身份验证失败时的理想响应(来自 web rest 客户端)。

{"msgDesc":"The username or password you entered is incorrect..","statusCode":401}

编辑:

response.toString() 返回

Response{protocol=http/1.1, code=401, message=Unauthorized, url=http://192.168.0.104:8080/mutterfly-server/j_spring_security_check?j_username=s@s.s&j_password=1}

response.body().toString() 返回

okhttp3.internal.http.RealResponseBody@528ae030

我想获取响应正文中的msgDesc。有什么方法可以返回这个字符串吗？

Answer 1

试试这个:

switch (response.code()){
        case 401:
           JsonObject object=new JsonObject(response.body().string());
           String body=object.getString("msgDesc");
           break;
}