java - 计算平均时间(hh :mm:ss) of a 24 hour clock

Question

我在 HHMMSS 23:00:00, 1:00:00 有时间。所以平均时间应该是00:00:00。我在 Java 中这样做。但是我不明白逻辑

我已经访问了这个链接' Find average of time in (hh mm ss) format in java '显示乘以 60，但如果时间在 23:00:00 和 1:00:00 之后，这将不起作用。

public static String calculateAverageOfTime(String timeInHHmmss) {
String[] split = timeInHHmmss.split(" ");
long seconds = 0;
for (String timestr : split) {
    String[] hhmmss = timestr.split(":");
    seconds += Integer.valueOf(hhmmss[0]) * 60 * 60;
    seconds += Integer.valueOf(hhmmss[1]) * 60;
    seconds += Integer.valueOf(hhmmss[2]);
}
seconds /= split.length;
long hh = seconds / 60 / 60;
long mm = (seconds / 60) % 60;
long ss = seconds % 60;
return String.format("%02d:%02d:%02d", hh,mm,ss);}

Answer 1

考虑到时间是按时间顺序排列的，所以在“23:00:00 1:00:00”中，1:00:00表示第二天凌晨1点，可以使用下面的calculateAverageOfTime方法变体

public static String calculateAverageOfTime(String timeInHHmmss) {
String[] split = timeInHHmmss.split(" ");
long seconds = 0;
long lastSeconds = 0;

for (String timestr : split) {
    String[] hhmmss = timestr.split(":");
    long currentSeconds = 0;

    currentSeconds += Integer.valueOf(hhmmss[0]) * 60 * 60;
    currentSeconds += Integer.valueOf(hhmmss[1]) * 60;
    currentSeconds += Integer.valueOf(hhmmss[2]);

    if (currentSeconds < lastSeconds)
        currentSeconds += 24 * 60 * 60; //next day
    seconds += currentSeconds;
    lastSeconds = currentSeconds;

}
seconds /= split.length;

long hh = (seconds / 60 / 60) % 24;
long mm = (seconds / 60) % 60;
long ss = seconds % 60;
return String.format("%02d:%02d:%02d", hh,mm,ss);}