java - if 条件被忽略

Question

这段代码应该检查密码长度是否合适，但如果密码长度大于或等于 16，它会跳过 if 条件并且不打印句子。

/* This bit of the coe just checks the length of the password */
if (Password.length() >= 8) {
    if (Password.length() <= 10) {
        System.out.println("Medium length of password");
    }
}
else if (Password.length() < 8) {
    System.out.println("Bruv youre asking to be hacked");
} 
else if (i >= 10) {
    if (Password.length() <= 13) {
        System.out.println("Good password length");
    }
    /* The part that fails */
    else if (Password.length() >= 16) {
        System.out.println("Great password length");
    }        
} 

如果密码长度大于或等于 16，代码应输出“Great password length”，但如果密码长度大于或等于 16，则不会输出任何内容

Answer 1

if(Password.length() >= 8)和 else if(Password.length() < 8)覆盖所有可能的密码长度，因此永远不会达到以下条件。

你应该以一种不那么困惑的方式组织你的条件:

if (Password.length() < 8) {
    System.out.println("Bruv youre asking to be hacked");
} else if (Password.length() >= 8 && Password.length() <= 10) {
    System.out.println("Medium length of password");
} else if (Password.length() > 10 and Password.length() <= 13) {
    System.out.println("Good password length");
} else if (Password.length() > 13 && Password.length() < 16) {
    ... // you might want to output something for passwords of length between 13 and 16
} else {
    System.out.println("Great password length");
}

甚至更好

if (Password.length() < 8) {
    System.out.println("Bruv youre asking to be hacked");
} else if (Password.length() <= 10) {
    System.out.println("Medium length of password");
} else if (Password.length() <= 13) {
    System.out.println("Good password length");
} else if (Password.length() < 16) {
    ... // you might want to output something for passwords of length between 13 and 16
} else {
    System.out.println("Great password length");
}