java - HttpClient:如何从现有连接获取底层套接字？

Question

我正在使用 HttpClient 4.02 通过代理创建连接(使用 CONNECT 方法)以隧道连接到远程服务器。 HttpClient 对此非常方便，但我是 API 的新手，看不到如何获取隧道连接的底层 Socket。

以下代码取自:http://svn.apache.org/repos/asf/httpcomponents/httpclient/tags/4.0.1/httpclient/src/examples/org/apache/http/examples/client/ClientExecuteProxy.java

    // make sure to use a proxy that supports CONNECT
    HttpHost target = new HttpHost("target.server.net", 443, "https");
    HttpHost proxy = new HttpHost("some.proxy.net", 8080, "http");

    // general setup
    SchemeRegistry supportedSchemes = new SchemeRegistry();

    // Register the "http" and "https" protocol schemes, they are
    // required by the default operator to look up socket factories.
    supportedSchemes.register(new Scheme("http", 
            PlainSocketFactory.getSocketFactory(), 80));
    supportedSchemes.register(new Scheme("https", 
            SSLSocketFactory.getSocketFactory(), 443));

    // prepare parameters
    HttpParams params = new BasicHttpParams();
    HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);

    ClientConnectionManager ccm = new ThreadSafeClientConnManager(params, 
            supportedSchemes);

    DefaultHttpClient httpclient = new DefaultHttpClient(ccm, params);

    httpclient.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY, proxy);

    HttpGet req = new HttpGet("/");

    System.out.println("executing request to " + target + " via " + proxy);
    HttpResponse rsp = httpclient.execute(target, req);
    HttpEntity entity = rsp.getEntity();

这很好地建立了连接，但是有没有办法获取底层 Socket，以便我使用自定义协议(protocol)与 target.server.net 上的服务器对话？

Answer 1

在项目的 JIRA 中打开变更请求。这个功能被忽略了。虽然从 3.x 中组装一个等效的 ProxyClient 应该是相当微不足道的，但将一个与 HttpClient 的库存版本一起发布是有意义的。

编辑:

从 4.2 版开始可用。参见 http://hc.apache.org/httpcomponents-client-4.3.x/httpclient/apidocs/org/apache/http/impl/client/ProxyClient.html