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java - 在二维字符数组中查找单词

转载 作者:塔克拉玛干 更新时间:2023-11-02 08:25:52 26 4
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什么样的方法可以很容易地在这样的谜题上找到给定的单词?我正在使用 Java。感谢您的帮助。

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最佳答案

有趣的问题。我将首先通过水平、垂直和对角线(在两个方向)遍历拼图来构建“可能的单词持有者”列表(可能包含给定单词之一的字符序列)来解决这个问题。然后我会在每个获得的“可能的单词持有者”中查看给定的单词(或其相反)是否存在(在 Java 中使用 contains() 方法)。这是我用 Java 编写的代码。我还没有正确测试它,但我想它可以工作!

import java.util.HashSet;
import java.util.LinkedHashSet;
import java.util.Set;

public class WordPuzzle {

public Set<String> findWords(char[][] puzzle, Set<String> words) {
Set<String> foundWords = new HashSet<String>();
int minimumWordLength = findMinimumWordLength(words);
Set<String> possibleWords = findPossibleWords(puzzle, minimumWordLength);
for(String word : words) {
for(String possibleWord : possibleWords) {
if(possibleWord.contains(word) || possibleWord.contains(new StringBuffer(word).reverse())) {
foundWords.add(word);
break;
}
}
}
return foundWords;
}

private int findMinimumWordLength(Set<String> words) {
int minimumLength = Integer.MAX_VALUE;
for(String word : words) {
if(word.length() < minimumLength)
minimumLength = word.length();
}
return minimumLength;
}

private Set<String> findPossibleWords(char[][] puzzle, int minimumWordLength) {
Set<String> possibleWords = new LinkedHashSet<String>();
int dimension = puzzle.length; //Assuming puzzle is square
if(dimension >= minimumWordLength) {
/* Every row in the puzzle is added as a possible word holder */
for(int i = 0; i < dimension; i++) {
if(puzzle[i].length >= minimumWordLength) {
possibleWords.add(new String(puzzle[i]));
}
}
/* Every column in the puzzle is added as a possible word holder */
for(int i = 0; i < dimension; i++) {
StringBuffer temp = new StringBuffer();
for(int j = 0; j < dimension; j++) {
temp = temp.append(puzzle[j][i]);
}
possibleWords.add(new String(temp));
}
/* Adding principle diagonal word holders */
StringBuffer temp1 = new StringBuffer();
StringBuffer temp2 = new StringBuffer();
for(int i = 0; i < dimension; i++) {
temp1 = temp1.append(puzzle[i][i]);
temp2 = temp2.append(puzzle[i][dimension - i - 1]);
}
possibleWords.add(new String(temp1));
possibleWords.add(new String(temp2));
/* Adding non-principle diagonal word holders */
for(int i = 1; i < dimension - minimumWordLength; i++) {
temp1 = new StringBuffer();
temp2 = new StringBuffer();
StringBuffer temp3 = new StringBuffer();
StringBuffer temp4 = new StringBuffer();
for(int j = i, k = 0; j < dimension && k < dimension; j++, k++) {
temp1 = temp1.append(puzzle[j][k]);
temp2 = temp2.append(puzzle[k][j]);
temp3 = temp3.append(puzzle[dimension - j - 1][k]);
temp4 = temp4.append(puzzle[dimension - k - 1][j]);
}
possibleWords.add(new String(temp1));
possibleWords.add(new String(temp2));
possibleWords.add(new String(temp3));
possibleWords.add(new String(temp4));
}
}
return possibleWords;
}

public static void main(String args[]) {
WordPuzzle program = new WordPuzzle();
char[][] puzzle = {
{'F','Y','Y','H','N','R','D'},
{'R','L','J','C','I','N','U'},
{'A','A','W','A','A','H','R'},
{'N','T','K','L','P','N','E'},
{'C','I','L','F','S','A','P'},
{'E','O','G','O','T','P','N'},
{'H','P','O','L','A','N','D'}
};
Set<String> words = new HashSet<String>();
words.add("FRANCE");
words.add("POLAND");
words.add("INDIA");
words.add("JAPAN");
words.add("USA");
words.add("HOLLAND");
Set<String> wordsFound = program.findWords(puzzle, words);
for(String word : wordsFound) {
System.out.println(word);
}
}
}

关于java - 在二维字符数组中查找单词,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5955107/

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