java - 我想使用 StringTokenizer 搜索字符串，但我要查找的字符串中有一个分隔符 - Java

Question

我有一个名为 quotes.txt 的外部文件，我将向您展示该文件的一些内容:

1 Everybody's always telling me one thing and out the other.
2 I love criticism just so long as it's unqualified praise.
3 The difference between 'involvement' and 'commitment' is like an eggs-and-ham 
  breakfast: the chicken was 'involved' - the pig was 'committed'.

我使用了这个:StringTokenizer str = new StringTokenizer(line, ".'");

这是搜索的代码:

String line = "";
boolean wordFound = false;

while((line = bufRead.readLine()) != null) {
    while(str.hasMoreTokens()) {
       String next = str.nextToken();
       if(next.equalsIgnoreCase(targetWord) {
            wordFound = true;
            output = line;
            break;
       }
    }

    if(wordFound) break;
    else output = "Quote not found";
}

现在，我想在第 1 行和第 2 行中搜索字符串 "Everybody's" 和 "it's" 但它不起作用，因为撇号是分隔符。如果我删除该分隔符，那么我将无法搜索 "involvement"、"commitment"、"involved" 和 “committed” 在第 3 行。

我可以用什么合适的代码来解决这个问题？请帮忙，谢谢。

Answer 1

我建议为此使用正则表达式 ( the Pattern class ) 而不是 StringTokenizer。例如:

final Pattern targetWordPattern =
    Pattern.compile("\\b" + Pattern.quote(targetWord) + "\\b",
                    Pattern.CASE_INSENSITIVE);

String line = "";
boolean wordFound = false;

while((line = bufRead.readLine()) != null) {
    if(targetWordPattern.matcher(line).find()) {
        wordFound = true;
        break;
    }
    else
        output = "Quote not found";
}