java - 如何使用从 Spring MVC 发回的 JSON 对象填充 jQuery 数据表的行？

Question

我有一个 Java (Spring MVC) 后端，它返回 POJO 作为 JSON 对象，如下所示:

@RequestMapping(value = "/getWidgetsByType", method = RequestMethod.POST)
public @ResponseBody List<WidgetVO> getWidgetsByType(@RequestParam("type") String type)
{
    return widgetDAO.getWidgetsByType(token);
}   

public class WidgetVO {
    private String type;
    private String name;
    private boolean isAwesome;

    // Getters and setters, etc.
}

在前端，我试图调用 /getWidgetsByType来自 jQuery $.getJSON调用，然后使用返回的 JSON 结果来填充 datatable .具体来说，我希望数据表出现在 <div> 中。页面加载时当前为空的标记如下:

<div id="#table-to-display"></div>

var t = getTypeFromDOM();

$.getJSON(
    url: "/getWidgetsByType",
    data: {
        type: t
    },
    success: function() {
        // How do I extract the JSON version of the List<WidgetVO>'s coming
        // back from the server and use them to populate the table?
        $("#table-to-display").datatable();
    }
);

我想要 datatable包含与 WidgetVO 的字段相同的列 (类型、名称、isAwesome)，全部为 String值(无渲染器等)。

在此先感谢您的帮助!

Answer 1

1. Controller

@RequestMapping(value = "/json", method = RequestMethod.GET)
public
@ResponseBody
String listUsersJson(ModelMap model) throws JSONException {
    int no=1;
    JSONArray userArray = new JSONArray();
    for (TileType tT: tD.getAll()){   
        String n=Integer.toString(no);
        String id=Integer.toString(tT.getTileTypeId());          
        String[] value =
        {n,
         tT.getTileTypeName(),
         tT.getTileTypeDensity()         
        };   
        userArray.put(value);
        no++;
    }
    String x=userArray.toString();
    String replace1=x.replace("{", "[");
    String replace2=replace1.replace("}","]");
    String replace3=replace2.replace(":",",");
   return ("{\"aaData\":"+replace3+"}");        
}

2.道

 @Override
public List<TileType> getAll() {
    Session session=HibernateUtil.getSessionFactory().openSession();
    List<TileType>list=new ArrayList<TileType>();
    try{
    Query query=session.createQuery("from TileType T order by T.tileTypeId DESC");
    list=query.list();
    }
    catch(HibernateException he){}
return list;
   }

3.Javascript

var table = $('#example').dataTable({
     "sPaginationType": "full_numbers",
    "sAjaxSource": "/data/tipeTile/json",
    "sDom": "<'row'<'col-xs-6'l><'col-xs-6'f>r>t<'row'<'col-xs-6'i><'col-xs-6'p>>",
    "sPaginationType": "bootstrap",
    "oLanguage": {
        "sLengthMenu": "_MENU_ records per page",
        "sSearch": ""
    }
         }); 

4.HTML

  <table cellpadding="0" cellspacing="0" border="0" class="table table-striped table-bordered" id="example">
                            <thead>
                                <tr>
                                    <th style="width: 50px">No</th>
                                    <th>Name</th>
                                    <th>Density</th>

                                </tr>
                            </thead>
                            <tbody>

                            </tbody>
                        </table>

希望对你有帮助