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android - 将 EditText 添加到警报对话框。

转载 作者:塔克拉玛干 更新时间:2023-11-02 08:16:54 24 4
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我有以下创建警报对话框的代码,我向其中添加了两个编辑文本,但是一旦我运行该应用程序,EditText 中的值将不会被检索并且我的应用程序因 NullPointerException 而崩溃:

代码是:

AlertDialog.Builder alert = new AlertDialog.Builder(this);
LayoutInflater inflater=this.getLayoutInflater();
final EditText usernameInput=(EditText)findViewById(R.id.dialogusername);
final EditText passwordInput=(EditText)findViewById(R.id.dialogpassword);
alert.setView(inflater.inflate(R.layout.dialog,null));
alert.setTitle("Enter Password");
alert.setMessage("Enter password to remove the app:");
alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
//provide user with caution before uninstalling
//also here should be added a AsyncTask that going to read the password and once its checked the password is correct the app will be removed
value1=usernameInput.getText().toString();
value2=passwordInput.getText().toString();
if(value1.equals(null)&&value2.equals(null))
{Toast.makeText(context, "Enter username and password", Toast.LENGTH_SHORT).show();}
}
});
});
alert.show();

最佳答案

感谢大家对我问题的回答,我想我已经找到了我在上面发布的问题的解决方案:

AlertDialog.Builder alert = new AlertDialog.Builder(MyFeedActivity.this);
LayoutInflater inflater=MyFeedActivity.this.getLayoutInflater();
//this is what I did to added the layout to the alert dialog
View layout=inflater.inflate(R.layout.dialog,null);
alert.setView(layout);
final EditText usernameInput=(EditText)layout.findViewById(R.id.dialogusername);
final EditText passwordInput=(EditText)layout.findViewById(R.id.dialogpassword);

我认为问题是我无法在警报对话框中获取 EidtText,但是通过上面的代码,一切正常。

关于android - 将 EditText 添加到警报对话框。,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13584063/

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