ios - NSPredicate 不适用于 ios 中的过滤

Question

我试过通过 NSPredicate 进行过滤。它在 NSMutableArray 中不起作用，但我在 Array 中试过并且它工作正常。

使用数组的工作代码:

filterArray=[NSMutableArray arrayWithObjects:@"Yvan",@"Balu",@"Srinath",@"Aswin",@"Ram", nil];
NSPredicate *bPredicate =[NSPredicate predicateWithFormat:@"SELF beginswith[c] 'r'"];
NSArray *resultAr = [resultArray filteredArrayUsingPredicate:bPredicate];
NSLog(@"Output %@",resultAr);

正确生成:

Output (
Srinath,
Ram
)

我尝试使用包含字典数据的 NSMutableArray，但它不起作用。

构建结果数组是:

for(int i=0;i<[priceArray count];i++)
    {
        cellDict=[[NSMutableDictionary alloc]init];
        NSString *nameStr=nameArray[i];
        [cellDict setObject:nameStr forKey:@"Name"];
        [cellDict setObject:@([splPriceArray[i] intValue]) forKey:@"Percentage"];
        [cellDict setObject:@([priceArray[i] intValue]) forKey:@"Price"];
        [resultArray addObject:cellDict];
    }

结果数组:

(
        {
        Name = "Black Eyed Peas";
        Percentage = 0;
        Price = 80;
    },
        {
        Name = "Black Gram";
        Percentage = 0;
        Price = 56;
    },
        {
        Name = "Channa White";
        Percentage = 0;
        Price = 100;
    },
        {
        Name = "Double Beans";
        Percentage = 0;
        Price = 95;
    },
        {
        Name = "Gram Dall";
        Percentage = 0;
        Price = 100;
    },
        {
        Name = "Green Moong Dal";
        Percentage = 0;
        Price = 150;
    },
        {
        Name = "Ground Nut";
        Percentage = 0;
        Price = 140;
    },
        {
        Name = "Moong Dal";
        Percentage = 0;
        Price = 75;
    },
        {
        Name = "Orid Dal";
        Percentage = 0;
        Price = 100;
    },
        {
        Name = "Toor Dal";
        Percentage = 0;
        Price = 150;
    }
) 

尝试过的谓词是:

//  NSPredicate *predit=[NSPredicate predicateWithFormat:@"Price contains[c] '100'"];

NSPredicate *pred=[NSPredicate predicateWithFormat:@"(Price == %@) AND (Percentage == %@)", @"100",@"0"];

NSArray *resultAr = [resultArray filteredArrayUsingPredicate:predit];

以上是正确的方法还是有更好的方法来实现它以获得:

expected output:
(
            {
            Name = "Channa White";
            Percentage = 0;
            Price = 100;
        },
            {
            Name = "Gram Dall";
            Percentage = 0;
            Price = 100;
        },          
            {
            Name = "Orid Dal";
            Percentage = 0;
            Price = 100;
        }
) 

Answer 1

1. 应该是Price不是price，应该是Percentage不是percentage
2. 我猜 Percentage 是 NSNumber 的类型

我测试

    NSDictionary * dic1 = @{
                        @"Name" : @"Black Eyed Peas",
                        @"Percentage":@(0),
                        @"Price" : @(80),
                        };
    NSDictionary * dic2 = @{
                        @"Name" : @"Black Eyed Peas",
                        @"Percentage":@(0),
                        @"Price" : @(100),
                        };
    NSMutableArray * mutableArray = [[NSMutableArray alloc] initWithArray:@[dic1,dic2]];
    NSPredicate *pred= [NSPredicate predicateWithFormat:@"(Price == %@) AND (Percentage == %@)", @(100),@(0)];

    NSArray *resultAr = [mutableArray filteredArrayUsingPredicate:pred];
    NSLog(@"%@",resultAr);

日志

2015-07-20 22:11:44.535 OCTest[2192:79846] (
    {
    Name = "Black Eyed Peas";
    Percentage = 0;
    Price = 100;
}
)