android - 正则表达式验证 PAN 卡号

Question

我看过this question和 this blog对于 PAN 正则表达式。 [A-Z]{5}[0-9]{4}[A-Z]{1}。但我的问题比这更广泛。

在 PAN 卡号中:

1) The first three letters are sequence of alphabets from AAA to zzz
2) The fourth character informs about the type of holder of the Card. Each assesse is unique:`

    C — Company
    P — Person
    H — HUF(Hindu Undivided Family)
    F — Firm
    A — Association of Persons (AOP)
    T — AOP (Trust)
    B — Body of Individuals (BOI)
    L — Local Authority
    J — Artificial Judicial Person
    G — Government


3) The fifth character of the PAN is the first character
    (a) of the surname / last name of the person, in the case of 
a "Personal" PAN card, where the fourth character is "P" or
    (b) of the name of the Entity/ Trust/ Society/ Organisation
in the case of Company/ HUF/ Firm/ AOP/ BOI/ Local Authority/ Artificial Jurdical Person/ Govt,
where the fourth character is "C","H","F","A","T","B","L","J","G".

4) The last character is a alphabetic check digit.

我希望正则表达式以此为基础进行检查。由于我在另一个 EditText 中得到了 Name of the person 或 Organization，因此我需要进一步验证第 4 和第 5 个字母。

原来是 [A-Z]{3}[C,H,F,A,T,B,L,J,G,P]{1}**第五个字符的东西** [0-9]{4}[A-Z]{1}

我不知道该怎样写东西。

以编程方式，它可以完成，someone has done it in rails但是可以通过正则表达式来完成吗？怎么办？

Answer 1

可以与 matches() 一起使用的正则表达式是根据用户的额外输入形成的，并且后视检查前面的第 4 个字符。如果第 4 个字母是 P，我们检查姓氏中的第一个字母，如果第 4 个字母不是 P，我们检查实体名称中的第一个字母:

String rx = "[A-Z]{3}([CHFATBLJGP])(?:(?<=P)" + c1 + "|(?<!P)" + c2 + ")[0-9]{4}[A-Z]";

Sample code :

String c1 = "S"; // First letter in surname coming from the EditText (with P before)
String c2 = "F"; // First letter in name coming from another EditText (not with P before)
String pan = "AWSPS1234Z"; // true
System.out.println(pan.matches("[A-Z]{3}([CHFATBLJGP])(?:(?<=P)" + c1 + "|(?<!P)" + c2 + ")[0-9]{4}[A-Z]"));
pan = "AWSCF1234Z"; // true
System.out.println(pan.matches("[A-Z]{3}([CHFATBLJGP])(?:(?<=P)" + c1 + "|(?<!P)" + c2 + ")[0-9]{4}[A-Z]"));
pan = "AWSCS1234Z"; // false
System.out.println(pan.matches("[A-Z]{3}([CHFATBLJGP])(?:(?<=P)" + c1 + "|(?<!P)" + c2 + ")[0-9]{4}[A-Z]"));