java - 当 if 语句失败时返回上一个 if 语句

Question

我 1 周前才开始使用 Java 编程，对于所有糟糕的代码，我深表歉意。我一直在从我曾经玩过的游戏中重新创建一个“优化系统”，只是因为我认为这对于初学者项目来说是个好主意。该系统根据成功几率来改进装备。当您获得更高的精炼度时，百分比几率会下降。

我的项目中的一种精炼方法是，每次失败的精炼都不会将精炼级别重置为 0，而是每次失败时都会将精炼级别降低 1。

我已经成功创建了一个失败时重置为 0 的方法，但似乎无法弄清楚如何在失败时将级别降低 1。

所以我的问题是，如何让我的“细化级别”在失败时减少 1，而不是重置为 0。此外，控制台需要在失败时返回到之前的 IF 语句，否则它将无法工作。

这是我的尝试:

import java.util.Random;

public class Tisha {

    public static void main(String[] args) throws InterruptedException {

        if (new Random().nextDouble() <= 0.535) {
            System.out.println("Refine successful  -  Refine level 1");
        } else {
            System.out.println("Refine failed  -  Refine reset");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.335) {
            System.out.println("Refine successful  -  Refine level 2");
        } else {
            System.out.println("Refine failed  -  Refine level 1");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.335) {
            System.out.println("Refine successful  -  Refine level 3");
        } else {
            System.out.println("Refine failed  -  Refine level 2");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.335) {
            System.out.println("Refine successful  -  Refine level 4");
        } else {
            System.out.println("Refine failed  -  Refine level 3");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.335) {
            System.out.println("Refine successful  -  Refine level 5");
        } else {
            System.out.println("Refine failed  -  Refine level 4");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.335) {
            System.out.println("Refine successful  -  Refine level 6");
        } else {
            System.out.println("Refine failed  -  Refine level 5");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.335) {
            System.out.println("Refine successful  -  Refine level 7");
        } else {
            System.out.println("Refine failed  -  Refine level 6");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.335) {
            System.out.println("Refine successful  -  Refine level 8");
        } else {
            System.out.println("Refine failed  -  Refine level 7");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.285) {
            System.out.println("Refine successful  -  Refine level 9");
        } else {
            System.out.println("Refine failed  -  Refine level 8");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.235) {
            System.out.println("Refine successful  -  Refine level 10");
        } else {
            System.out.println("Refine failed  -  Refine level 9");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.155) {
            System.out.println("Refine successful  -  Refine level 11");
        } else {
            System.out.println("Refine failed  -  Refine level 10");
        }

        Thread.sleep(250);

        if (new Random().nextDouble() <= 0.085) {
            System.out.println("Refine successful  -  Refine level 12");
        } else {
            System.out.println("Refine failed  -  Refine level 11");
        }
    }

}

输出:

Refine successful  -  Refine level 1
Refine failed  -  Refine level 1
Refine failed  -  Refine level 2
Refine failed  -  Refine level 3
Refine failed  -  Refine level 4
Refine successful  -  Refine level 6
Refine failed  -  Refine level 6
Refine failed  -  Refine level 7
Refine successful  -  Refine level 9
Refine failed  -  Refine level 9
Refine successful  -  Refine level 11
Refine successful  -  Refine level 12

Process finished with exit code 0

对不起，我警告过你，代码乱七八糟。

Answer 1

将您的细化级别设置为一个变量，并相应地增加或减少。

int refinementLevel = 0;

if (new Random().nextDouble() <= 0.155) {
  refinementLevel++;
  System.out.println("Refine successful  -  Refine level "+refinementLevel);
} else {
  refinementLevel--;
  System.out.println("Refine failed  -  Refine level "+refinementLevel);
}