ios - 我可以在没有 goBack 导航的情况下获取 UIWebView 的以前的 url 吗？

Question

如果是UIWebView canGoBack，我可以在没有返回导航的情况下获取之前的url吗？

我知道我可以自己实现一个历史堆栈，但我相信 UIWebView 会维护一个历史堆栈，因此它可以前后移动。有没有办法访问此历史记录？

编辑:我的意思是:有没有办法从 UIWebView 访问此历史记录？

Answer 1

我喜欢 RAJA 所说的关于将 URL 存储在 NSArray 中的想法，但他并没有真正实现它，所以现在就开始吧。

MySubClass.h

@interface MySubClass : MySuperClass

// I am assuming that you are creating your UIWebView in interface builder
@property (nonatomic, strong) IBOutlet UIWebView *myWebView;    

// I'm going to make the initial array that stores the URLs private to
// this class but if we wanted to access that array outside of this class
// we can using this method, but we will return a NSArray not a NSMutableArray
// so it can't be modified outside of this class.
- (NSArray *)visitedURLs;

@end

MySubClass.m

#import "MySubClass.h"

// Our private interface   
@interface MySubClass()

// Our private mutable array
@property (nonatomic, strong) NSMutableArray *visitedURLsArray;  

@end  

@implementation MySubClass

- (void)viewDidLoad
{ 
    // Check if the visitedURLsArray is nil and if it is alloc init
    if(visitedURLsArray == nil) 
        visitedURLsArray = [[NSMutableArray alloc] init];
}

- (NSArray *)visitedURLs
{
    return (NSArray *)visitedURLsArray;
}

- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
{
    // If you don't wish to store the URL every time you hit refresh where you
    // could end up with the same URL being add multiple times you could also 
    // check what the last URL was in the array and if it is the same ignore it
    if(![[visitedURLsArray lastObject] isEqualToString:[[request URL] absoluteString]]) {

        // Every time this method is hit, so every time a request is sent into the 
        // the webView. We want to store the requested URL in the array.
        // so this would create a log of visited URLs with the last one added being
        // the last URL visited. 
        [visitedURLsArray addObject:[[request URL] absoluteString]];
    }
    return YES;
}

@end

重要提示

此答案基于原始问题，该问题未提及与用户正在使用的 backbone.js 有任何关系。