ios - UIBezierPath:在 iPad 上创建的控制点多于 iPhone？

Question

我有以下代码(基于 this 答案)来创建一个“可变形”的圆形 <> 方形。

它在 iPhone 上运行良好:

但在 iPad 上不太好(运行相同版本的 iOS - 10):

代码是:

-(UIBezierPath*)circlePathWithCenter:(CGPoint)center andRadius:(CGFloat)radius {
    UIBezierPath *circlePath = [UIBezierPath bezierPath];
    [circlePath addArcWithCenter:center radius:radius startAngle:-M_PI endAngle:-M_PI/2 clockwise:YES];
    [circlePath addArcWithCenter:center radius:radius startAngle:-M_PI/2 endAngle:0 clockwise:YES];
    [circlePath addArcWithCenter:center radius:radius startAngle:0 endAngle:M_PI/2 clockwise:YES];
    [circlePath addArcWithCenter:center radius:radius startAngle:M_PI/2 endAngle:M_PI clockwise:YES];
    [circlePath closePath];

    NSLog(@"%@", [circlePath debugDescription]);

    return circlePath;
}

- (UIBezierPath *)squarePathWithCenter:(CGPoint)center andSize:(CGFloat)size
{
    CGFloat startX = center.x-size/2;
    CGFloat startY = center.y-size/2;

    UIBezierPath *squarePath = [UIBezierPath bezierPath];
    [squarePath moveToPoint:CGPointMake(startX, startY)];
    [squarePath addLineToPoint:squarePath.currentPoint];
    [squarePath addLineToPoint:CGPointMake(startX+size, startY)];
    [squarePath addLineToPoint:squarePath.currentPoint];
    [squarePath addLineToPoint:CGPointMake(startX+size, startY+size)];
    [squarePath addLineToPoint:squarePath.currentPoint];
    [squarePath addLineToPoint:CGPointMake(startX, startY+size)];
    [squarePath addLineToPoint:squarePath.currentPoint];
    [squarePath closePath];

    NSLog(@"%@", [squarePath debugDescription]);

    return squarePath;
}

动画代码为:

CABasicAnimation *animation = [CABasicAnimation animationWithKeyPath:@"path"];
animation.duration = 0.5;
animation.timingFunction = [CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionEaseInEaseOut];

animation.fromValue = (__bridge id)(_innerShape.path);
animation.toValue = (__bridge id)(_innerSquare.CGPath);
_innerShape.path = _innerSquare.CGPath;

[_innerShape addAnimation:animation forKey:@"animatePath"];

在仔细检查路径时，我注意到 iPad 版本(运行相同的代码)上有更多的“曲线”点。从上一期的讨论来看，我认为控制点的数量需要相同才能得到平滑的过渡。

设备之间预期的点数是否不同？有没有更可靠的方法来实现可变形的形状？

iPad调试圆圈:

<UIBezierPath: 0x6c4f0d0; <MoveTo {13.5, 45.000004}>,
 <CurveTo {44.999996, 13.5} {13.499998, 27.603035} {27.603027, 13.500002}>,
 <CurveTo {45, 13.5} {44.999996, 13.5} {45, 13.5}>,
 <LineTo {45, 13.5}>,
 <CurveTo {76.5, 45} {62.396969, 13.499999} {76.5, 27.603031}>,
 <CurveTo {76.5, 45} {76.5, 45} {76.5, 45}>,
 <LineTo {76.5, 45}>,
 <CurveTo {45, 76.5} {76.5, 62.396969} {62.396969, 76.5}>,
 <CurveTo {45, 76.5} {45, 76.5} {45, 76.5}>,
 <LineTo {45, 76.5}>,
 <CurveTo {13.5, 45} {27.603031, 76.5} {13.499999, 62.396969}>,
 <CurveTo {13.5, 44.999996} {13.5, 45} {13.5, 44.999996}>,
 <Close>

iPhone 版:

<UIBezierPath: 0x6180000b24e0; <MoveTo {13.5, 44.999999999999993}>,
 <CurveTo {45, 13.5} {13.500000000000002, 27.603030380330004} {27.603030380330011, 13.499999999999998}>,
 <LineTo {45, 13.5}>,
 <CurveTo {76.5, 45} {62.396969619669989, 13.500000000000002} {76.5, 27.603030380330011}>,
 <LineTo {76.5, 45}>,
 <CurveTo {45, 76.5} {76.5, 62.396969619669989} {62.396969619669989, 76.5}>,
 <LineTo {45, 76.5}>,
 <CurveTo {13.5, 45.000000000000007} {27.603030380330011, 76.5} {13.500000000000002, 62.396969619669996}>,
 <Close>

两者都是正方形:

<UIBezierPath: 0x6000000b0f80; <MoveTo {29.25, 29.25}>,
 <LineTo {29.25, 29.25}>,
 <LineTo {60.75, 29.25}>,
 <LineTo {60.75, 29.25}>,
 <LineTo {60.75, 60.75}>,
 <LineTo {60.75, 60.75}>,
 <LineTo {29.25, 60.75}>,
 <LineTo {29.25, 60.75}>,
 <Close>

Answer 1

如果在两条路径之间转换，重要的是它们具有相同数量的段。

有两种基本方法:

1. 一种方法是将圆创建为多条线段，然后将相同数量的线段组合成正方形。您只需要使用足够多的线段，使圆看起来是圆的:

   static NSInteger segments = 360;
   
   - (UIBezierPath*)circlePathWithCenter:(CGPoint)center andRadius:(CGFloat)radius {
   
       CGFloat startAngle = -M_PI * 3.0 / 4.0;
       CGPoint point = CGPointMake(radius * cos(startAngle) + center.x, radius * sinf(startAngle) + center.y);
   
       UIBezierPath *path = [UIBezierPath bezierPath];
       [path moveToPoint:point];
   
       for (NSInteger angle = 1; angle <= segments; angle++) {
           point = CGPointMake(radius * cos(startAngle + ((CGFloat)angle / 360.0 * M_PI * 2.0)) + center.x,
                               radius * sin(startAngle + ((CGFloat)angle / 360.0 * M_PI * 2.0)) + center.y);
           [path addLineToPoint:point];
       }
   
       return path;
   }
   
   - (UIBezierPath *)squarePathWithCenter:(CGPoint)center andSize:(CGFloat)size {
       CGFloat startX = center.x-size/2;
       CGFloat startY = center.y-size/2;
   
       CGFloat endX = startX+size;
       CGFloat endY = startY;
   
       UIBezierPath *path = [UIBezierPath bezierPath];
       CGPoint point = CGPointMake(startX, startY);
       [path moveToPoint:point];
   
       for (NSInteger i = 1; i <= segments / 4; i++) {
           CGPoint point = CGPointMake(startX + (endX - startX) * (CGFloat) i / 90.0,
                                       startY + (endY - startY) * (CGFloat) i / 90.0);
           [path addLineToPoint:point];
       }
   
       startX = endX; startY = endY;
       endY += size;
   
       for (NSInteger i = 1; i <= segments / 4; i++) {
           CGPoint point = CGPointMake(startX + (endX - startX) * (CGFloat) i / 90.0,
                                       startY + (endY - startY) * (CGFloat) i / 90.0);
           [path addLineToPoint:point];
       }
   
       startX = endX; startY = endY;
       endX -= size;
   
       for (NSInteger i = 1; i <= segments / 4; i++) {
           CGPoint point = CGPointMake(startX + (endX - startX) * (CGFloat) i / 90.0,
                                       startY + (endY - startY) * (CGFloat) i / 90.0);
           [path addLineToPoint:point];
       }
   
       startX = endX; startY = endY;
       endY -= size;
   
       for (NSInteger i = 1; i <= segments / 4; i++) {
           CGPoint point = CGPointMake(startX + (endX - startX) * (CGFloat) i / 90.0,
                                       startY + (endY - startY) * (CGFloat) i / 90.0);
           [path addLineToPoint:point];
       }
   
       return path;
   }
   

   

2. 或者，您可以使用圆弧，但您可能希望确保线段和圆弧在两条路径中一对一地匹配。例如，我可以将正方形渲染为一系列零半径圆弧，它们之间有线段，并将圆渲染为一系列全尺寸圆弧，它们之间有零长度线段。这样，对 moveToPoint、addArcWithCenter 和 addLineToPoint 的每次调用都会一一对应:

   - (UIBezierPath*)circlePathWithCenter:(CGPoint)center andRadius:(CGFloat)radius {
       UIBezierPath *path = [UIBezierPath bezierPath];
   
       CGFloat startAngle = -M_PI;
   
       [path moveToPoint:CGPointMake(center.x - radius, center.y)];
   
       for (NSInteger angle = 0; angle < 4; angle++) {
           [path addArcWithCenter:center radius:radius startAngle:startAngle endAngle:startAngle + M_PI_2 clockwise:true];
           [path addLineToPoint:path.currentPoint];
           startAngle += M_PI_2;
       }
   
       return path;
   }
   
   - (UIBezierPath *)squarePathWithCenter:(CGPoint)center andSize:(CGFloat)size {
       CGFloat startX = center.x-size/2;
       CGFloat startY = center.y-size/2;
       CGFloat angle = -M_PI;
   
       CGFloat endX = startX+size;
       CGFloat endY = startY;
   
       UIBezierPath *path = [UIBezierPath bezierPath];
       CGPoint point = CGPointMake(startX, startY);
       [path moveToPoint:point];
   
       [path addArcWithCenter:point radius:0 startAngle:angle endAngle:angle + M_PI_2 clockwise:true];
       point = CGPointMake(endX, endY);
       [path addLineToPoint:point];
   
       angle += M_PI_2;
       startX = endX; startY = endY;
       endY += size;
   
       [path addArcWithCenter:point radius:0 startAngle:angle endAngle:angle + M_PI_2 clockwise:true];
       point = CGPointMake(endX, endY);
       [path addLineToPoint:point];
   
       angle += M_PI_2;
       startX = endX; startY = endY;
       endX -= size;
   
       [path addArcWithCenter:point radius:0 startAngle:angle endAngle:angle + M_PI_2 clockwise:true];
       point = CGPointMake(endX, endY);
       [path addLineToPoint:point];
   
       angle += M_PI_2;
       startX = endX; startY = endY;
       endY -= size;
   
       [path addArcWithCenter:point radius:0 startAngle:angle endAngle:angle + M_PI_2 clockwise:true];
       point = CGPointMake(endX, endY);
       [path addLineToPoint:point];
   
       return path;
   }
   

   产生:

   

这两者会产生不同的效果，所以这取决于您的目的。