android - 选择器与 android :drawable ="@color/transparent" attribute

Question

<!--  Active tab -->
<item android:state_selected="true" android:state_focused="false"
    android:state_pressed="false" android:drawable="@drawable/tab_bg_selected" />
<!--  Inactive tab -->
<item android:state_selected="false" android:state_focused="false"
    android:state_pressed="false" android:drawable="@drawable/tab_bg_unselected" />
<!--  Pressed tab -->
<item android:state_pressed="true" android:drawable="@color/transparent" />
<!--  Selected tab (using d-pad) -->
<item android:state_focused="true" android:state_selected="true"
    android:state_pressed="false" android:drawable="@color/transparent" />

有没有办法在这种选择器中得到错误我想使用这种o选择器但是我在android:drawable="@color/transparent中得到一个错误我得到这个错误当我运行它时

我想尽一切办法让它发挥作用

Answer 1

替换

android:drawable="@color/transparent"

与

android:drawable="@android:color/transparent"

你应该引用android命名空间