java - 使用 twitter API 版本 1.1 检索 user_timeline 的最简单 Java 示例

Question

我一直在寻找一个使用 Twitter 1.1 API 的简单 Java 示例，但找不到。使用此处发布的 PHP 示例:Simplest PHP example for retrieving user_timeline with Twitter API version 1.1和其他一些 Stackoverflow 帖子，我能够想出以下工作示例。

public void testUserTimelineWithAuthSample() throws Exception {
    //This will read the timeline of your account.
    String method = "GET";
    String url = "https://api.twitter.com/1.1/statuses/user_timeline.json";

    String oAuthConsumerKey = "Your value here.";
    String oAuthConsumerSecret = "Your value here."; //<--- DO NOT SHARE THIS VALUE

    String oAuthAccessToken = "Your value here.";
    String oAuthAccessTokenSecret = "Your value here."; //<--- DO NOT SHARE THIS VALUE

    String oAuthNonce = String.valueOf(System.currentTimeMillis());
    String oAuthSignatureMethod = "HMAC-SHA1";
    String oAuthTimestamp = time();
    String oAuthVersion = "1.0";

    String signatureBaseString1 = method;
    String signatureBaseString2 = url;
    String signatureBaseString3Templ = "oauth_consumer_key=%s&oauth_nonce=%s&oauth_signature_method=%s&oauth_timestamp=%s&oauth_token=%s&oauth_version=%s";
    String signatureBaseString3 = String.format(signatureBaseString3Templ,
                                                    oAuthConsumerKey, 
                                                    oAuthNonce,
                                                    oAuthSignatureMethod,
                                                    oAuthTimestamp,
                                                    oAuthAccessToken,
                                                    oAuthVersion);

    String signatureBaseStringTemplate = "%s&%s&%s";
    String signatureBaseString =  String.format(signatureBaseStringTemplate, 
                                                                URLEncoder.encode(signatureBaseString1, "UTF-8"), 
                                                                URLEncoder.encode(signatureBaseString2, "UTF-8"),
                                                                URLEncoder.encode(signatureBaseString3, "UTF-8"));

    System.out.println("signatureBaseString: "+signatureBaseString);

    String compositeKey = URLEncoder.encode(oAuthConsumerSecret, "UTF-8") + "&" + URLEncoder.encode(oAuthAccessTokenSecret, "UTF-8");

    String oAuthSignature =  computeSignature(signatureBaseString, compositeKey);
    System.out.println("oAuthSignature       : "+oAuthSignature);

    String oAuthSignatureEncoded = URLEncoder.encode(oAuthSignature, "UTF-8");
    System.out.println("oAuthSignatureEncoded: "+oAuthSignatureEncoded);

    String authorizationHeaderValueTempl = "OAuth oauth_consumer_key=\"%s\", oauth_nonce=\"%s\", oauth_signature=\"%s\", oauth_signature_method=\"%s\", oauth_timestamp=\"%s\", oauth_token=\"%s\", oauth_version=\"%s\"";

    String authorizationHeaderValue = String.format(authorizationHeaderValueTempl,
                                                        oAuthConsumerKey,
                                                        oAuthNonce,
                                                        oAuthSignatureEncoded,
                                                        oAuthSignatureMethod,
                                                        oAuthTimestamp,
                                                        oAuthAccessToken,
                                                        oAuthVersion);
    System.out.println("authorizationHeaderValue: "+authorizationHeaderValue);


    System.out.println("url: "+url);
    System.out.println("authorizationHeaderValue:"+authorizationHeaderValue);

    GetMethod getMethod = new GetMethod(url);
    getMethod.addRequestHeader("Authorization", authorizationHeaderValue);
    HttpClient cli = new HttpClient();
    int status = cli.executeMethod(getMethod);
    System.out.println("Status:"+status);

    long responseContentLength = getMethod.getResponseContentLength();
    System.out.println("responseContentLength:"+responseContentLength);

    String response = getMethod.getResponseBodyAsString();  
    System.out.println("response: "+response);
}


private static String computeSignature(String baseString, String keyString) throws GeneralSecurityException, UnsupportedEncodingException, Exception 
{
    SecretKey secretKey = null;

    byte[] keyBytes = keyString.getBytes();
    secretKey = new SecretKeySpec(keyBytes, "HmacSHA1");

    Mac mac = Mac.getInstance("HmacSHA1");

    mac.init(secretKey);

    byte[] text = baseString.getBytes();

    return new String(Base64.encodeBase64(mac.doFinal(text))).trim();
}

private String time() {
    long millis = System.currentTimeMillis();
    long secs = millis / 1000;
    return String.valueOf( secs );
}

但是，如果我向 url 添加参数，例如:

String url = "https://api.twitter.com/1.1/statuses/user_timeline.json?screen_name=twitterapi&count=2";

我得到:

响应:{"errors":[{"message":"Could not authentication you","code":32}]}

知道哪里出了问题吗？

Answer 1

这对于使用新的 Twitter API 1.1 的时间线非常有效

1) 下载twitter4j-core-3.0.3.jar http://twitter4j.org/en/2) 尝试使用此代码:

private static final String TWITTER_CONSUMER_KEY = "xxxxxxxxxxxxxxxxxx";
private static final String TWITTER_SECRET_KEY = "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx";
private static final String TWITTER_ACCESS_TOKEN = "xxxxxxxxxxxxxxxxxxxxxxx";
private static final String TWITTER_ACCESS_TOKEN_SECRET = "xxxxxxxxxxxxxxxxxxxxxxxxx";

ConfigurationBuilder cb = new ConfigurationBuilder();
cb.setDebugEnabled(true)
    .setOAuthConsumerKey(TWITTER_CONSUMER_KEY)
    .setOAuthConsumerSecret(TWITTER_SECRET_KEY)
    .setOAuthAccessToken(TWITTER_ACCESS_TOKEN)
    .setOAuthAccessTokenSecret(TWITTER_ACCESS_TOKEN_SECRET);
TwitterFactory tf = new TwitterFactory(cb.build());
Twitter twitter = tf.getInstance();
try {
    Query query = new Query("MrEdPanama");
    QueryResult result;
    do {
        result = twitter.search(query);
        List<Status> tweets = result.getTweets();
        for (Status tweet : tweets) {
            System.out.println("@" + tweet.getUser().getScreenName() + " - " + tweet.getText());
        }
    } while ((query = result.nextQuery()) != null);
    System.exit(0);
} catch (TwitterException te) {
    te.printStackTrace();
    System.out.println("Failed to search tweets: " + te.getMessage());
    System.exit(-1);
}