java - 如何在java中获取源字符串中大括号内的字符串数组

Question

java中有一个字符串对象，其内容为:

String sourceString="This {is} a sample {string} that {contains} {substrings} inside curly {braces}";

我想要一个字符串数组，其内容为:{is},{string},{contains},{substrings}{braces}

以下是我为获得结果而编写的代码，但我得到的输出是:

"{is} a sample {string} that {contains} {substrings} inside curly {braces}"

所以，基本上它是获取第一个左大括号和最后一个右大括号之间的所有字符。

// Source string
String sourceString="This {is} a samle {string} that {contains} {substrings} inside curly {braces}";

// Regular expression to get the values between curly braces (there is a mistake, I guess)
String regex="\\{(.*)\\}";
Matcher matcher = Pattern.compile(regex).matcher(sourceString);

while (matcher.find()) {
    System.out.println(matcher.group(0));
}

Answer 1

发现了一些谷歌搜索 this解决方案，它给了我关于模式的想法

花一些时间在 Lesson: Regular Expressions 上带来了提供此示例所需的库和功能...

String exp = "\\{(.*?)\\}";

String value = "This {is} a samle {string} that {contains} {substrings} inside curly {braces}";

Pattern pattern = Pattern.compile(exp);
Matcher matcher = pattern.matcher(value);

List<String> matches = new ArrayList<String>(5);
while (matcher.find()) {
    String group = matcher.group();
    matches.add(group);
}

String[] groups = matches.toArray(new String[matches.size()]);
System.out.println(Arrays.toString(groups));

哪些输出

[{is}, {string}, {contains}, {substrings}, {braces}]