java - 我如何在 Java 中执行以下 curl 命令

Question

如何在 Java URLConnection 中实现以下 curl 命令

curl -X PUT \
  -H "X-Parse-Application-Id: " \
  -H "X-Parse-REST-API-Key: " \
  -H "Content-Type: application/json" \
  -d '{"score":73453}'

提前致谢

Answer 1

使用 URLConnection 的派生类这是 HttpURLConnection你可以轻松做到。

URL myURL = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)myURL.openConnection();
myURLConnection.setRequestMethod("PUT");
myURLConnection.setRequestProperty("X-Parse-Application-Id", "");
myURLConnection.setRequestProperty("X-Parse-REST-API-Key", "");
myURLConnection.setRequestProperty("Content-Type", "application/json");
myURLConnection.setUseCaches(false);
myURLConnection.setDoInput(true);
myURLConnection.setDoOutput(true);
myURLConnection.connect();

JSONObject jsonParam = new JSONObject();
jsonParam.put("score", "73453");

OutputStream os = myURLConnection.getOutputStream();
os.write(URLEncoder.encode(jsonParam.toString(),"UTF-8"));
os.close();

对于 curl -X GET\-H "X-Parse-Application-Id: "\-H "X-Parse-REST-API-Key: "\-G\--data-urlencode 'include =游戏

String charset = "UTF-8";
String query = String.format("include=%s", URLEncoder.encode("game", charset));
URL myURL = new URL(serviceURL+"?"+query);
HttpURLConnection myURLConnection = (HttpURLConnection)myURL.openConnection();
myURLConnection.setRequestMethod("GET");
myURLConnection.setRequestProperty("X-Parse-Application-Id", "");
myURLConnection.setRequestProperty("X-Parse-REST-API-Key", "");
myURLConnection.setUseCaches(false);
myURLConnection.setDoInput(true);
myURLConnection.setDoOutput(true);
myURLConnection.connect();