java - 如何排除 Java 对象属性作为 JSON 字符串的一部分？

Question

我有一个 Java POJO。很少有属性与列表<>一起存在。将此对象转换为 JSON 字符串时，我想排除列表属性，那么为此使用什么注解呢？

public class StudentResultSummary {
    private String totMarks;
    private String avgMarks;
    private List<StudentResult> resultList = new ArrayList<StudentResult>();
}

转换为 JSON:

StudentResultSummary resultSummary = new StudentResultSummary();
Json json = new Json();
policySummary = json.encode(resultSummary);

如何确保字段 resultList 不包含在 JSON 响应中？

Answer 1

来自 Chris Seline's answer :

Any fields you don't want serialized in general you should use the "transient" modifier, and this also applies to json serializers (at least it does to a few that I have used, including gson).

If you don't want name to show up in the serialized json give it a transient keyword, eg:

private transient String name;