java - 原始 int 也是 Comparable 吗？

Question

我刚看到一个 Java 泛型教程，它似乎使用原始 int、float 等作为扩展 Comparable 的对象

    public class MaximumTest {
   // determines the largest of three Comparable objects

   public static <T extends Comparable<T>> T maximum(T x, T y, T z) {
      T max = x;   // assume x is initially the largest

      if(y.compareTo(max) > 0) {
         max = y;   // y is the largest so far
      }

      if(z.compareTo(max) > 0) {
         max = z;   // z is the largest now                 
      }
      return max;   // returns the largest object   
   }

   public static void main(String args[]) {
      System.out.printf("Max of %d, %d and %d is %d\n\n", 
         3, 4, 5, maximum( 3, 4, 5 ));

      System.out.printf("Max of %.1f,%.1f and %.1f is %.1f\n\n",
         6.6, 8.8, 7.7, maximum( 6.6, 8.8, 7.7 ));

      System.out.printf("Max of %s, %s and %s is %s\n","pear",
         "apple", "orange", maximum("pear", "apple", "orange"));
   }
}

primitive 能否以某种方式成为 Comparable 对象？

Answer 1

原语将自动装箱为实现Comparable 的包装器对象。int val = 3; 将变成一个 Integer autoboxing and unboxing java