java - 使用策略对 Java 程序进行分级

Question

评分政策是

2个小测验10分

1次期中考试和1次期末考试，各100分

期末考试占成绩的 50%，期中考试占 25%，两次测验合计占 25%。

还应该给出一个字母等级

这是老师给的

import java.util.*;
import java.io.*;

public class Assign7{
  public static void main(String[] args)throws Exception{



    Scanner myIn = new Scanner( new File("scores.txt") );



    System.out.println( myIn.nextLine() +"  avg  "+"letter");

    while( myIn.hasNext() ){
       name = myIn.Next();
       q1 = myIn.nextInt();
       q2 = myIn.nextInt();
       m = myIn.nextInt();
       f = myIn.nextInt();
       Record myR = new Record( name, q1,q2,m,f);
       System.out.println(myR);

    } 
  }
}

这就是我到目前为止的想法，但是我不断收到三个错误消息

赋值7.java:28;错误:表达式的非法开始公共(public)字符串 toString(){

赋值7.java:28;错误:';'预期的公共(public)字符串 toString(){

Assign7.java:33: 错误:解析时到达文件末尾

谁能告诉我如何解决这个错误(这是我的代码)

class Assign7{
  private double finalScore;
  private double private_quiz1;
  private double private_quiz2;
  private double private_midTerm;
  private double private_final;
  private final char grade;


  public Assign7(double finalScore){
    private_quiz1 = 1.25;
    private_quiz2 = 1.25;
    private_midTerm = 0.25;
    private_final = 0.50;

        if (finalScore >= 90) {
            grade = 'A';
        } else if (finalScore >= 80) {
            grade = 'B';
        } else if (finalScore >= 70) {
            grade = 'C';
        } else if (finalScore>= 60) {
            grade = 'D';
        } else {
            grade = 'F';


  public String toString(){
    return finalScore+":"+private_quiz1+":"+private_quiz2+":"+private_midTerm+":"+private_final;

  }
} 

Answer 1

您缺少一个 } 来结束 public Assign7 的声明以及您最后一个 if 语句。

public Assign7(double finalScore){
    private_quiz1 = 1.25;
    private_quiz2 = 1.25;
    private_midTerm = 0.25;
    private_final = 0.50;

    if (finalScore >= 90) {
        grade = 'A';
    } else if (finalScore >= 80) {
        grade = 'B';
    } else if (finalScore >= 70) {
        grade = 'C';
    } else if (finalScore>= 60) {
        grade = 'D';
    } else {
        grade = 'F';
    } // <===== ADD THIS
} // <============= ADD THIS

其他答案提供了有关确保始终有匹配牙套的建议。这些也是可靠的答案。