java - keyPressed 事件在第一次重复时变慢

Question

好吧，我很抱歉这是一个非常奇怪的问题，但它让我发疯。

我通过以下方式处理游戏的 WASD 移动:

Action ClassWASDKeyPressed = new ClassWASDKeyPressed();
Action ClassWASDKeyReleased = new ClassWASDKeyReleased();
BitKeys movementBitKeys = new BitKeys(); //for WASD movement key pressed/releases

//pressed
theDesktop.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke("W"), "wButtonPress");
theDesktop.getActionMap().put("wButtonPress", ClassWASDKeyPressed);
theDesktop.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke("A"), "aButtonPress");
theDesktop.getActionMap().put("aButtonPress", ClassWASDKeyPressed);
theDesktop.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke("S"), "sButtonPress");
theDesktop.getActionMap().put("sButtonPress", ClassWASDKeyPressed);
theDesktop.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke("D"), "dButtonPress");
theDesktop.getActionMap().put("dButtonPress", ClassWASDKeyPressed);
//released
theDesktop.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke("released W"), "wButtonRelease");
theDesktop.getActionMap().put("wButtonRelease", ClassWASDKeyReleased);
theDesktop.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke("released A"), "aButtonRelease");
theDesktop.getActionMap().put("aButtonRelease", ClassWASDKeyReleased);
theDesktop.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke("released S"), "sButtonRelease");
theDesktop.getActionMap().put("sButtonRelease", ClassWASDKeyReleased);
theDesktop.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(KeyStroke.getKeyStroke("released D"), "dButtonRelease");
theDesktop.getActionMap().put("dButtonRelease", ClassWASDKeyReleased);

这是两个 Action 类:

class ClassWASDKeyPressed extends AbstractAction {
    private static final long serialVersionUID = 1L;

    public void actionPerformed(ActionEvent e) {
        if (chatTextField.isFocusOwner() == false){
            if (e.getActionCommand().equals("w")){
                keyPressed(87);
            } else if(e.getActionCommand().equals("a")){
                keyPressed(65);
            } else if(e.getActionCommand().equals("s")){
                keyPressed(83);
            } else if(e.getActionCommand().equals("d")){
                keyPressed(68);
            }
        }
    }
}

class ClassWASDKeyReleased extends AbstractAction {
    private static final long serialVersionUID = 1L;

    public void actionPerformed(ActionEvent e) {
        if (chatTextField.isFocusOwner() == false){
            if (e.getActionCommand().equals("w")){
                keyReleased(87);
            } else if(e.getActionCommand().equals("a")){
                keyReleased(65);
            } else if(e.getActionCommand().equals("s")){
                keyReleased(83);
            } else if(e.getActionCommand().equals("d")){
                keyReleased(68);
            }
        }
    }
}

逻辑如下:

public void keyPressed(int e) {
    long endTime = System.nanoTime();
    long elapsedTime = endTime - startTime;
    double elapsedTimeSeconds = (double)elapsedTime / 1000000000.0;

    if (elapsedTimeSeconds < .125){ //let them move 8 times a second
        logger.info("KeyPressed (QUICK): " + elapsedTimeSeconds);
    } else {
        logger.info("KeyPressed (VALID): " + elapsedTimeSeconds);
        //logger.debug("Key Pressed: " + e.getKeyChar());  //FOR TROUBLESHOOTING
        movementBitKeys.keyPressed(e);
        //movementBitKeys.showKeyList();  //FOR TROUBLESHOOTING

        if (movementBitKeys.isKeyPressed(87) && !movementBitKeys.isKeyPressed(68) && !movementBitKeys.isKeyPressed(83) && !movementBitKeys.isKeyPressed(65)){
            requestCharacterMove("North");
        }
        if (movementBitKeys.isKeyPressed(87) && movementBitKeys.isKeyPressed(68) && !movementBitKeys.isKeyPressed(83) && !movementBitKeys.isKeyPressed(65)){
            requestCharacterMove("NorthEast");
        }
        if (movementBitKeys.isKeyPressed(87) && !movementBitKeys.isKeyPressed(68) && !movementBitKeys.isKeyPressed(83) && movementBitKeys.isKeyPressed(65)){
            requestCharacterMove("NorthWest");
        }
        if (!movementBitKeys.isKeyPressed(87) && movementBitKeys.isKeyPressed(68) && !movementBitKeys.isKeyPressed(83) && !movementBitKeys.isKeyPressed(65)){
            requestCharacterMove("East");
        }
        if (!movementBitKeys.isKeyPressed(87) && !movementBitKeys.isKeyPressed(68) && movementBitKeys.isKeyPressed(83) && !movementBitKeys.isKeyPressed(65)){
            requestCharacterMove("South");
        }
        if (!movementBitKeys.isKeyPressed(87) && movementBitKeys.isKeyPressed(68) && movementBitKeys.isKeyPressed(83) && !movementBitKeys.isKeyPressed(65)){
            requestCharacterMove("SouthEast");
        }
        if (!movementBitKeys.isKeyPressed(87) && !movementBitKeys.isKeyPressed(68) && movementBitKeys.isKeyPressed(83) && movementBitKeys.isKeyPressed(65)){
            requestCharacterMove("SouthWest");
        }
        if (!movementBitKeys.isKeyPressed(87) && !movementBitKeys.isKeyPressed(68) && !movementBitKeys.isKeyPressed(83) && movementBitKeys.isKeyPressed(65)){
            requestCharacterMove("West");
        }
        startTime = endTime;
    }
}

public void keyReleased(int e) {
    //logger.debug("Key Released: " + e.getKeyChar());  //FOR TROUBLESHOOTING
    movementBitKeys.keyReleased(e);
    //movementBitKeys.showKeyList();  //FOR TROUBLESHOOTING
}

public void keyTyped(int e) {
    // not used - but in case I ever want it
}

还有 BitSet 类:

package com.jayavon.game.helper;

import java.util.BitSet;

public class BitKeys{

    private BitSet keyBits = new BitSet(256);

    public void keyPressed(final int keyCode) {
        keyBits.set(keyCode);
    }

    public void keyReleased(final int keyCode) {
        keyBits.clear(keyCode);
    }

    public void keyTyped(final int keyCode) {
        // don't care
    }

    public boolean isKeyPressed(final int keyCode) {
        return keyBits.get(keyCode);
    }

    public void showKeyList(){
        System.out.println(keyBits.toString());
    }

}

我的问题是，当您在第一次和第二次“移动”之间按住其中一个移动键时，比所需的 0.125 毫秒等待时间长得多。这是一些示例数据:

第 1 组:

6059 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(有效):2.567790275

6620 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(有效):0.560479937

6670 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.05044696710 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.093605166750 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(有效):0.129943376

6791 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.040095056821 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.070989976851 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.1023786866902 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(有效):0.152006677

第 2 组:

9690 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(有效):2.03802468

10272 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(有效):0.582025645

10322 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.05474932310342 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.06989004210372 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.10079021210412 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(有效):0.141337411

10462 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.04948345810462 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.04972038110512 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(快速):0.09888852410542 [AWT-EventQueue-0] 信息 com.jayavon.game.client.MyClient - KeyPressed(有效):0.128729361

现在是提问时间。显然，您第一次移动所用的时间很长，具体取决于多长时间，所以这是有道理的。我不明白为什么第二个“运动”是在 0.5 左右而不是接近 0.125。正如您从数据中看到的那样，按住键时第三步和第四步的触发速度如此之快，以至于它们小于 .125。

谁能帮我解决这个问题？任何以任何方式改进我的代码的建议都将是巨大的帮助。毫秒数。

Answer 1

由于@aioobe 的巨大帮助，我解决了这个问题。

Timer timer = new Timer();
timer.schedule(new TimerTask() {
    public void run() {
        checkKeyStrokes();
    }
}, 0, 0135);

public void checkKeyStrokes(){
    if (movementBitKeys.isKeyPressed(87)){ //w
        keyPressed(87);
    }
    if (movementBitKeys.isKeyPressed(65)){ //a
        keyPressed(65);
    }
    if (movementBitKeys.isKeyPressed(83)){ //s
        keyPressed(83);
    }
    if (movementBitKeys.isKeyPressed(68)){ //d
        keyPressed(68);
    }
}

希望这对其他人有帮助!!!