java - 将数字单词替换为数字

Question

我正在尝试将所有数字单词 0-9 替换为字符串中相应的数字 0-9。

我创建了两个数字单词和数字数组，然后尝试使用替换循环来更改句子。

不确定我做错了什么。

我正在引用我的 getNoDigitWordString 方法。

import java.util.*;
public class StringProcessor {
private String noSpaces;
private String input, noVowels;
private String noDigitWords;
private int numOfWords = 0, uppercaseLetters = 0,
            numOfDigits = 0, digitWords = 0;
private String [] wordDigits = {"zero","one", "two", "three","four",
        "five", "six", "seven", "eight", "nine"};
private String [] digits = {"0", "1", "2", "3", "4",
        "5", "6", "7", "8", "9"};


public StringProcessor()
{
    input = "";
}

public StringProcessor(String s)
{
    StringTokenizer str = new StringTokenizer(s);
    numOfWords = str.countTokens();

    for (int i = 0; i < s.length(); i++)
    {
        if (Character.isUpperCase(s.charAt(i)))
            uppercaseLetters++;
    }

    for (int i = 0; i < s.length(); i++)
    {
        if (Character.isDigit(s.charAt(i)))
            numOfDigits++;
    }

    String [] strSplit = s.split(" ");
    for(int i = 0; i < strSplit.length; i++)
    {
        for (int j = 0; j < wordDigits.length; j++)
        {
            if (strSplit[i].equalsIgnoreCase(wordDigits[j]))
                    digitWords++;
        }
    }


    noSpaces = s.replace(" ","");
    noVowels = s.replaceAll("[aeiou]", "-");

    for(int i = 0; i < 10; i++)
    {
        noDigitWords = s.replace("wordDigits[i]", "digits[i]");
    }
}

public void setString(String s)
{
    input = s;
}

public String getString()
{
    return input;
}

public int wordCount()
{
    return numOfWords;
}

public int uppercaseCount()
{
    return uppercaseLetters;
}

public int digitCount()
{
    return numOfDigits;
}

public int digitWordCount()
{
    return digitWords;
}

public String getNoSpaceString()
{
    return noSpaces;
}

public String getNoVowelString()
{
    return noVowels;
}

public String getNoDigitWordString()
{
    return noDigitWords;
}

public static void main(String[] args)
{
    String input;
    Scanner keyboard = new Scanner(System.in);

    System.out.print("Enter a line of text: ");
    input = keyboard.nextLine();

    StringProcessor str = new StringProcessor(input);

    System.out.println("words: " + str.wordCount());
    System.out.println("uppercase: " + str.uppercaseCount());
    System.out.println("digits: " + str.digitCount());
    System.out.println("digit words " + str.digitWordCount());
    System.out.println("line with no spaces: " + str.getNoSpaceString());
    System.out.println("line with vowels replaced: " + str.getNoVowelString());
    System.out.println("line with digit words replaced: " + str.getNoDigitWordString());
}
}

谢谢。

Answer 1

这就是您要找的:

noDigitWords = s;
for(int i = 0; i < strSplit.length; i++)
{
    for (int j = 0; j < wordDigits.length; j++)
    {
        if (strSplit[i].equalsIgnoreCase(wordDigits[j])){
            noDigitWords = noDigitWords.replace(strSplit[i], digits[j]);
            break;
        }
    }
}

取而代之的是:

for(int i = 0; i < 10; i++)
{
    noDigitWords = s.replace("wordDigits[i]", "digits[i]");
}