java - 在java中定义大量变量

Question

我正在为我的计算机科学类(class)做一个项目。我的老师希望我们创建一个程序，其中包含一副纸牌，能够洗牌并发牌。他希望我们创建一个具有变量 suitName、suitValue、faceName 和 faceValue 的卡片类。我目前的代码如下所示:

//Construct Array
Card[] deck = new Card[52];
//Define cards
Card aceSpades = new Card("Spades", 1, "Ace", 1);
Card aceHearts = new Card("Hearts", 2, "Ace", 1);
Card aceClubs = new Card("Clubs", 3, "Ace", 1);
Card aceDiamonds = new Card("Diamonds", 4, "Ace", 1);
Card twoSpades = new Card("Spades", 1, "Two", 2);
Card twoHearts = new Card("Hearts", 2, "Two", 2);
Card twoClubs = new Card("Clubs", 3, "Two", 2);
Card twoDiamonds = new Card("Diamonds", 4, "Two", 2);
Card threeSpades = new Card("Spades", 1, "Three", 3);
Card threeHearts = new Card("Hearts", 2, "Three", 3);
Card threeClubs = new Card("Clubs", 3, "Three", 3);
Card threeDiamonds = new Card("Diamonds", 4, "Three", 3);
Card fourSpades = new Card("Spades", 1, "Four", 4);
Card fourHearts = new Card("Hearts", 2, "Four", 4);
Card fourClubs = new Card("Clubs", 3, "Four", 4);
Card fourDiamonds = new Card("Diamonds", 4, "Four", 4);
Card fiveSpades = new Card("Spades", 1, "Five", 5);
Card fiveHearts = new Card("Hearts", 2, "Five", 5);
Card fiveClubs = new Card("Clubs", 3, "Five", 5);
Card fiveDiamonds = new Card("Diamonds", 4, "Five", 5);
Card sixSpades = new Card("Spades", 1, "Six", 6);
Card sixHearts = new Card("Hearts", 2, "Six", 6);
Card sixClubs = new Card("Clubs", 3, "Six", 6);
Card sixDiamonds = new Card("Diamonds", 4, "Six", 6);
Card sevenSpades = new Card("Spades", 1, "Seven", 7);
Card sevenHearts = new Card("Hearts", 2, "Seven", 7);
Card sevenClubs = new Card("Clubs", 3, "Seven", 7);
Card sevenDiamonds = new Card("Diamonds", 4, "Seven", 7);
Card eightSpades = new Card("Spades", 1, "Eight", 8);
Card eightHearts = new Card("Hearts", 2, "Eight", 8);
Card eightClubs = new Card("Clubs", 3, "Eight", 8);
Card eightDiamonds = new Card("Diamonds", 4, "Eight", 8);
Card nineSpades = new Card("Spades", 1, "Nine", 9);
Card nineHearts = new Card("Hearts", 2, "Nine", 9);
Card nineClubs = new Card("Clubs", 3, "Nine", 9);
Card nineDiamonds = new Card("Diamonds", 4, "Nine", 9);
Card tenSpades = new Card("Spades", 1, "Ten", 10);
Card tenHearts = new Card("Hearts", 2, "Ten", 10);
Card tenClubs = new Card("Clubs", 3, "Ten", 10);
Card tenDiamonds = new Card("Diamonds", 4, "Ten", 10);
Card jackSpades = new Card("Spades", 1, "Jack", 11);
Card jackHearts = new Card("Hearts", 2, "Jack", 11);
Card jackClubs = new Card("Clubs", 3, "Jack", 11);
Card jackDiamonds = new Card("Diamonds", 4, "Jack", 11);
Card queenSpades = new Card("Spades", 1, "Queen", 12);
Card queenHearts = new Card("Hearts", 2, "Queen", 12);
Card queenClubs = new Card("Clubs", 3, "Queen", 12);
Card queenDiamonds = new Card("Diamonds", 4, "Queen", 12);
Card kingSpades = new Card("Spades", 1, "King", 13);
Card kingHearts = new Card("Hearts", 2, "King", 13);
Card kingClubs = new Card("Clubs", 3, "King", 13);
Card kingDiamonds = new Card("Diamonds", 4, "King", 13);
deck[0] = aceSpades;
deck[1] = aceHearts;
deck[2] = aceClubs;
deck[3] = aceDiamonds;
deck[4] = twoSpades;
deck[5] = twoHearts;
deck[6] = twoClubs;
deck[7] = twoDiamonds;
deck[8] = threeSpades;
deck[9] = threeHearts;
deck[10] = threeClubs;
deck[11] = threeDiamonds;
deck[12] = fourSpades;
deck[13] = fourHearts;
deck[14] = fourClubs;
deck[15] = fourDiamonds;
deck[16] = fiveSpades;
deck[17] = fiveHearts;
deck[18] = fiveClubs;
deck[19] = fiveDiamonds;
deck[20] = sixSpades;
deck[21] = sixHearts;
deck[22] = sixClubs;
deck[23] = sixDiamonds;
deck[24] = sevenSpades;
deck[25] = sevenHearts;
deck[26] = sevenClubs;
deck[27] = sevenDiamonds;
deck[28] = eightSpades;
deck[29] = eightHearts;
deck[30] = eightClubs;
deck[31] = eightDiamonds;
deck[32] = nineSpades;
deck[33] = nineHearts;
deck[34] = nineClubs;
deck[35] = nineDiamonds;
deck[36] = tenSpades;
deck[37] = tenHearts;
deck[38] = tenClubs;
deck[39] = tenDiamonds;
deck[40] = jackSpades;
deck[41] = jackHearts;
deck[42] = jackClubs;
deck[43] = jackDiamonds;
deck[44] = queenSpades;
deck[45] = queenHearts;
deck[46] = queenClubs;
deck[47] = queenDiamonds;
deck[48] = kingSpades;
deck[49] = kingHearts;
deck[50] = kingClubs;
deck[51] = kingDiamonds;

有没有更有效的方法来做到这一点

Answer 1

是的:

1. 直接分配到deck的元素中
2. 使用一个或多个循环遍历花色和值