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android - android PopupWindow 可以显示另一个 PopupWindow 吗?

转载 作者:塔克拉玛干 更新时间:2023-11-01 22:07:04 35 4
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android PopupWindow 可以显示另一个 PopupWindow 吗?可以同时打开多少个 PopupWindow?只有一个?

第一个PopupWindow正常显示。但是在单击按钮时(在第一个 PopupWindow contentview 中)我有一个异常(exception):

08-13 16:28:38.682: ERROR/AndroidRuntime(11760): FATAL EXCEPTION: main
android.view.WindowManager$BadTokenException: Unable to add window -- token android.view.ViewRootImpl$W@41286250 is not valid; is your activity running?
at android.view.ViewRootImpl.setView(ViewRootImpl.java:600)
at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:313)
at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:215)
at android.view.WindowManagerImpl$CompatModeWrapper.addView(WindowManagerImpl.java:140)
at android.view.Window$LocalWindowManager.addView(Window.java:537)
at android.widget.PopupWindow.invokePopup(PopupWindow.java:992)
at android.widget.PopupWindow.showAsDropDown(PopupWindow.java:901)
at org.example.qberticus.quickactions.BetterPopupWindow.showLikePopDownMenu(BetterPopupWindow.java:159)
at org.example.qberticus.quickactions.BetterPopupWindow.showLikePopDownMenu(BetterPopupWindow.java:129)
at name.antonsmirnov.android.popup.ui.MainActivity$1$1.run(MainActivity.java:44)
at android.app.Activity.runOnUiThread(Activity.java:4170)
at name.antonsmirnov.android.popup.ui.MainActivity$1.onClick(MainActivity.java:42)
at android.view.View.performClick(View.java:3558)
at android.view.View$PerformClick.run(View.java:14157)
at android.os.Handler.handleCallback(Handler.java:605)
at android.os.Handler.dispatchMessage(Handler.java:92)
at android.os.Looper.loop(Looper.java:137)
at android.app.ActivityThread.main(ActivityThread.java:4514)
at java.lang.reflect.Method.invokeNative(Native Method)
at java.lang.reflect.Method.invoke(Method.java:511)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:790)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:557)
at dalvik.system.NativeStart.main(Native Method)

代码是:

    @Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);

setContentView(R.layout.main);
bindControls();
initControls();
}

private Button button;

private void bindControls() {
button = (Button) findViewById(R.id.button);
}

private void initControls() {
initButton(button);
}

private void initButton(final Button button) {
button.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
final BetterPopupWindow window = new BetterPopupWindow(button);

View popupview = createPopupView();
window.setContentView(popupview);
runOnUiThread(new Runnable() {
public void run() {
window.showLikePopDownMenu();
}
});
}
});
}

private View createPopupView() {
View v = LayoutInflater.from(MainActivity.this).inflate(R.layout.window, null);
Button popupButton = (Button) v.findViewById(R.id.popupbutton);
initButton(popupButton);
return v;
}

最佳答案

玩过之后我发现

    window.showAtLocation(getWindow().getDecorView(), Gravity.CENTER, x, y);

工作正常,但是

    window.showAsDropDown(getWindow().getDecorView(), Gravity.CENTER, x, y);

引发异常!如果您将 showAtLocation(view) 与任何不同于 getWindow().getDecorView() 的 View 一起使用,您仍然会遇到异常。

关于android - android PopupWindow 可以显示另一个 PopupWindow 吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11932578/

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