java - 如何压缩这些大的 if 语句

Question

我已经研究这段代码一段时间了，终于完成了它，但是有什么方法可以压缩大量的 if 语句吗？

我已经尝试了我的编码知识范围内的一切，但似乎没有任何效果。

import java.util.Scanner;

public class AidanMRN{

    public static void main(String[] args){

        //Creating Variable "Number"
        int number;

        Scanner keyboard = new Scanner(System.in);

        //Storing Number
        System.out.println("Pick a number, 1 - 10");
        number = keyboard.nextInt();

        //If statements and Outputs
        if (number > 10)
            //Error message
            System.out.print("Error, " + number + " is higher than 10.\nPlease try again");
        if (number == 1)
            System.out.println("Roman Numeral: I");

        if (number == 2)
            System.out.println("Roman Numeral: II");

        if (number == 3)
            System.out.println("Roman Numeral: III");

        if (number == 4)
            System.out.println("Roman Numeral: IV");

        if (number == 5)
            System.out.println("Roman Numeral: V");

        if (number == 6)
            System.out.println("Roman Numeral: VI");

        if (number == 7)
            System.out.println("Roman Numeral: VII");

        if (number == 8)
            System.out.println("Roman Numeral: VIII");

        if (number == 9)
            System.out.println("Roman Numeral: IX");

        if (number == 10)
            System.out.println("Roman Numeral: X");
    }
}

Answer 1

你可以用这段代码有更短的 if 语句。

public static void main(String[] args) {
            String[] romanNumbers= {"I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX", "X"};

            int number;
            Scanner keyboard = new Scanner(System.in);
            //Storing Number
            System.out.println("Pick a number, 1 - 10");
            number = keyboard.nextInt();
            //If statements and Outputs
            if (number > 10 || number < 1)
                //Error message
                System.out.print("Error, " + number + " is higher than 10.\nPlease try again");
            else
                System.out.println("Roman Numeral: " + romanNumbers[number -1]);
        }
    }