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java - 在 servlet 的 jsp 页面中显示图像

转载 作者：塔克拉玛干 更新时间：2023-11-01 21:36:03 24 4
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<分区>

我的代码正在上传图像并将图像保存到我的服务器，但我需要在我的 jsp 页面中显示该图像。

上传图片的jsp

uploadImage.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>

<head><title>Image Upload</title></head>

<body>
  <form action="UploadImage" method="post" enctype="multipart/form-data" 
           name="productForm" id="productForm"><br><br>
    <table width="400px" align="center" border=0 style="background-color:ffeeff;">
      <tr>
        <td align="center" colspan=2 style="font-weight:bold;font-size:20pt;">
           Image Details</td>
      </tr>

      <tr>
        <td align="center" colspan=2>&nbsp;</td>
      </tr>

      <tr>
        <td>Image Link: </td>
        <td>
          <input type="file" name="file" id="file">
        <td>
      </tr>

      <tr>
        <td></td>
        <td><input type="submit" name="Submit" value="Submit"></td>
      </tr>
      <tr>
        <td colspan="2">&nbsp;

        </td>
      </tr>

    </table>
  </form>
</body>

</html>

小服务程序

上传图片

public class UploadImage extends HttpServlet {
    /**
     * 
     */

    private static final long serialVersionUID = 2082405235440894340L;

    public void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        File filenameImg;
        List<FileItem> items = null;
        try {
            items = new ServletFileUpload(new DiskFileItemFactory())
                    .parseRequest(request);
        } catch (FileUploadException e) {
            throw new ServletException("Cannot parse multipart request.", e);
        }

        for (FileItem item : items) {
            if (item.isFormField()) {
                // Process regular form fields here the same way as
                // request.getParameter().
                // You can get parameter name by
                item.getFieldName();
                // You can get parameter value by item.getString();
            } else {

                try{
                    // Process uploaded fields here.
                    String filename = FilenameUtils.getName(item.getName());
                    // Get filename.
                    String path = GetWebApplicationPathServlet.getContext().getRealPath("/images");

                    File file =  new File(path,filename);


                    //File file = new File("C:\\", filename);

                    // Define destination file.

                    item.write(file);
                    System.out.println("filename: "+filename);
                    System.out.println("file: "+file);
                    request.setAttribute("image", file);
                    filenameImg = file;
                    // Write to destination file.
                //  request.setAttribute("image", filename);
                }
                catch (Exception e) {
                    e.printStackTrace();
                }

            }
        }
        // Show result page.


        System.out.println("request"+request.getAttribute("image"));
        response.setContentType("image/jpeg"); 
        //request.getRequestDispatcher("result.jsp").forward(request, response);

        String nextJSP = "/result.jsp";
        RequestDispatcher dispatcher = getServletContext()
                .getRequestDispatcher(nextJSP);
        dispatcher.forward(request, response);

    }

}

结果.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"
    pageEncoding="ISO-8859-1"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<%=request.getParameter("image")%>

<img src="<%=request.getParameter("image")%>">
</body>
</html>

<%=request.getParameter("图像")%> 在 result.jsp 页面中返回为 null

帮助

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