java - 提取嵌套大括号内的数据

Question

我想分别提取第一个嵌套大括号和第二个嵌套大括号之间的内容。现在我完全坚持这个任何人都可以帮助我。我的文件 read.txt 包含以下数据。我只是把它读成一个字符串“s”。

  BufferedReader br=new BufferedReader(new FileReader("read.txt"));
    while(br.ready())
    {
        String s=br.readLine();
        System.out.println(s);

    }

输出

{ { "John", "ran" },                { "NOUN", "VERB" } },
{ { "The", "dog", "jumped"},        { "DET", "NOUN", "VERB" } },
{ {  "Mike","lives","in","Poland"}, {"NOUN","VERB","DET","NOUN"} },

即我的输出应该是这样的

  "John", "ran"    
  "NOUN", "VERB" 
  "The", "dog", "jumped"  
  "DET", "NOUN", "VERB" 
  "Mike","lives","in","Poland" 
  "NOUN","VERB","DET","NOUN"

Answer 1

使用这个正则表达式:

(?<=\{)(?!\s*\{)[^{}]+

查看 Regex Demo 中的匹配项.

在 Java 中:

Pattern regex = Pattern.compile("(?<=\\{)(?!\\s*\\{)[^{}]+");
Matcher regexMatcher = regex.matcher(subjectString);
while (regexMatcher.find()) {
    // matched text: regexMatcher.group()
}

解释

• 回顾 (?<=\{)断言当前位置之前的是 {
• 负前瞻 (?!\s*\{)断言后面的内容不是可选空格然后 {
• [^{}]+匹配任何不是 curl 的字符