android - 如何使用多部分形式的数据json将图像(位图)发送到android中的服务器

Question

我有上传图片到服务器的代码，它可以工作，

HttpEntity resEntity;

                HttpClient httpClient = new DefaultHttpClient();
                HttpPost post = new HttpPost(Constants.url_create_product);
                MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
                File file= new File(path);
                FileBody bin = new FileBody(file);

                reqEntity.addPart("phone", new StringBody(mPhoneNumber));
                reqEntity.addPart("prod_title", new StringBody(namapro));
                reqEntity.addPart("prod_price", new StringBody(hargapro));
                reqEntity.addPart("prod_desc", new StringBody(despro));
                reqEntity.addPart("prod_order", new StringBody(orderpro));
                reqEntity.addPart("prod_image", bin);

                post.setEntity(reqEntity);
                    HttpResponse response = httpClient.execute(post);
                resEntity = response.getEntity();
                String response_str = EntityUtils.toString(resEntity);
                Gson gson = new Gson(); 
                gson.toJson(response_str);
                 if (resEntity != null) {
                     Log.i("RESPONSE",response_str);
                     runOnUiThread(new Runnable(){
                            public void run() {
                                 try {
                                    Toast.makeText(getApplicationContext(),"Upload Complete. Check the server uploads directory.", Toast.LENGTH_LONG).show();
                                } catch (Exception e) {
                                    e.printStackTrace();
                                }
                               }
                        });
                 }

但我有菜单图像编辑器。该编辑器是裁剪图像，那是像这样的代码返回位图值

Bundle extras = data.getExtras();

                if (extras != null) {               
                    photo = extras.getParcelable("data");

                    mImageView.setImageBitmap(photo);
                }

                File f = new File(mImageCaptureUri.getPath());            

                if (f.exists()) f.delete();

                break;

我想问一下，如何解决将带有参数位图的图像发送到服务器。如您所知，我发送图像的代码现在使用参数路径(字符串)。

Answer 1

ByteArrayOutputStream baos = new ByteArrayOutputStream();
photo.compress(Bitmap.CompressFormat.JPEG, 100, baos);
byte[] imageBytes = baos.toByteArray();
String encodedImage = Base64.encodeToString(imageBytes, Base64.DEFAULT);

然后将此编码图像作为 String 发送，在您的服务器中您需要对其进行解码以获取图像本身。