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Android 获取所有联系人列表(姓名、电子邮件、电话)需要超过一分钟的时间来获取大约 700 个联系人

转载 作者:塔克拉玛干 更新时间:2023-11-01 21:31:02 24 4
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有什么办法可以缩短这个时间吗?我用光标运行并获取姓名、电话号码和电子邮件

如果我从查询循环中删除电话号码查询,它将在 3 秒内结束

知道如何改进该查询吗?

也许我在查询中做错了什么?

(显然我正在异步执行,但仍然......用户等不及的时间很长)

希望有人可以分享他对此的看法

这是我的代码

ContentResolver cr = getContentResolver();
Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
null, null, null, null);
if (cur.getCount() > 0) {
while (cur.moveToNext()) {
AddressBookEntity adr = new AddressBookEntity();
String id = cur.getString(cur
.getColumnIndex(ContactsContract.Contacts._ID));
String name = cur
.getString(cur
.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
adr.fullName = name;

Cursor emailCur = cr
.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Email.CONTACT_ID
+ " = ?", new String[] { id },
null);
while (emailCur.moveToNext()) {
// This would allow you get several email addresses
// if the email addresses were stored in an array
String email = emailCur
.getString(emailCur
.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
if (!Utils.IsNullOrEmptyString(email)) {
adr.email = email;
}

}
emailCur.close();

if (Integer
.parseInt(cur.getString(cur
.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
Cursor pCur = cr
.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID
+ " = ?",
new String[] { id }, null);
int phoneIndex = 0;
while (pCur.moveToNext()) {
String number = pCur.getString(pCur
.getColumnIndex(Phone.NUMBER));

String country = Utils.GetCountryFromNumber(
number, app);
number = Utils.GetFullPhoneNumber(number, app);
if (phoneIndex == 0) {
if (!Utils.IsNullOrEmptyString(number)) {
adr.contactAdressBookId = id;
adr.phoneNumber = number;
adr.userInsertedId = app.userCred.userId;
adr.country = country;
myContacts.add(adr);
}
} else {
if (!Utils.IsNullOrEmptyString(number)) {
AddressBookEntity adrMore = new AddressBookEntity();
adrMore.fullName = adrMore.fullName;
adrMore.country = adrMore.country;
adrMore.email = adrMore.email;
adrMore.phoneNumber = number;
adrMore.contactAdressBookId = id;
adrMore.country = country;
myContacts.add(adrMore);
}
}
}
pCur.close();
}
}
cur.close();

最佳答案

使用以下 59 个联系人的代码,我在模拟器上得到了以下结果:

      D  ╔══════ query execution stats ═══════
D ║ got 59 contacts
D ║ query took 0.012 s (12 ms)
D ╚════════════════════════════════════

好的,那是最好的时间,但平均时间是 25-35 毫秒(对于 59 个联系人),在一些 onClick 回调中添加以下代码并运行几次以获得平均时间,在你的情况下你应该得到 30 * 700/59 = ~300-400 毫秒,而不是 3 秒,更不用说一分钟了 ;)

它使用设置为 API 级别 18 中添加的 Contactables.CONTENT_URI 的 Uri,但您可以在为 18 之前的 API 设备构建时使用 ContactsContract.Data.CONTENT_URI

List<AddressBookContact> list = new LinkedList<AddressBookContact>();
LongSparseArray<AddressBookContact> array = new LongSparseArray<AddressBookContact>();
long start = System.currentTimeMillis();

String[] projection = {
ContactsContract.Data.MIMETYPE,
ContactsContract.Data.CONTACT_ID,
ContactsContract.Contacts.DISPLAY_NAME,
ContactsContract.CommonDataKinds.Contactables.DATA,
ContactsContract.CommonDataKinds.Contactables.TYPE,
};
String selection = ContactsContract.Data.MIMETYPE + " in (?, ?)";
String[] selectionArgs = {
ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE,
ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE,
};
String sortOrder = ContactsContract.Contacts.SORT_KEY_ALTERNATIVE;

Uri uri = ContactsContract.CommonDataKinds.Contactables.CONTENT_URI;
// we could also use Uri uri = ContactsContract.Data.CONTENT_URI;

// ok, let's work...
Cursor cursor = getContentResolver().query(uri, projection, selection, selectionArgs, sortOrder);

final int mimeTypeIdx = cursor.getColumnIndex(ContactsContract.Data.MIMETYPE);
final int idIdx = cursor.getColumnIndex(ContactsContract.Data.CONTACT_ID);
final int nameIdx = cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME);
final int dataIdx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Contactables.DATA);
final int typeIdx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Contactables.TYPE);

while (cursor.moveToNext()) {
long id = cursor.getLong(idIdx);
AddressBookContact addressBookContact = array.get(id);
if (addressBookContact == null) {
addressBookContact = new AddressBookContact(id, cursor.getString(nameIdx), getResources());
array.put(id, addressBookContact);
list.add(addressBookContact);
}
int type = cursor.getInt(typeIdx);
String data = cursor.getString(dataIdx);
String mimeType = cursor.getString(mimeTypeIdx);
if (mimeType.equals(ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE)) {
// mimeType == ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE
addressBookContact.addEmail(type, data);
} else {
// mimeType == ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE
addressBookContact.addPhone(type, data);
}
}
long ms = System.currentTimeMillis() - start;
cursor.close();

// done!!! show the results...
int i = 1;
for (AddressBookContact addressBookContact : list) {
Log.d(TAG, "AddressBookContact #" + i++ + ": " + addressBookContact.toString(true));
}
final String cOn = "<b><font color='#ff9900'>";
final String cOff = "</font></b>";
Spanned l1 = Html.fromHtml("got " + cOn + array.size() + cOff + " contacts<br/>");
Spanned l2 = Html.fromHtml("query took " + cOn + ms / 1000f + cOff + " s (" + cOn + ms + cOff + " ms)");

Log.d(TAG, "\n\n╔══════ query execution stats ═══════" );
Log.d(TAG, "║ " + l1);
Log.d(TAG, "║ " + l2);
Log.d(TAG, "╚════════════════════════════════════" );
SpannableStringBuilder msg = new SpannableStringBuilder().append(l1).append(l2);

LinearLayout ll = new LinearLayout(this);
ll.setOrientation(LinearLayout.VERTICAL);
TextView tv = new TextView(this);
tv.setTextSize(20);
tv.setBackgroundColor(0xff000033);
tv.setPadding(24, 8, 24, 24);
tv.setText(msg);
ll.addView(tv);
ListView lv = new ListView(this);
lv.setAdapter(new ArrayAdapter<AddressBookContact>(this, android.R.layout.simple_list_item_1, list));
ll.addView(lv);
new AlertDialog.Builder(this).setView(ll).setPositiveButton("close", null).create().show();

帮助器 AddressBookContact 类:

class AddressBookContact {
private long id;
private Resources res;
private String name;
private LongSparseArray<String> emails;
private LongSparseArray<String> phones;

AddressBookContact(long id, String name, Resources res) {
this.id = id;
this.name = name;
this.res = res;
}

@Override
public String toString() {
return toString(false);
}

public String toString(boolean rich) {
SpannableStringBuilder builder = new SpannableStringBuilder();
if (rich) {
builder.append("id: ").append(Long.toString(id))
.append(", name: ").append("\u001b[1m").append(name).append("\u001b[0m");
} else {
builder.append(name);
}

if (phones != null) {
builder.append("\n\tphones: ");
for (int i = 0; i < phones.size(); i++) {
int type = (int) phones.keyAt(i);
builder.append(ContactsContract.CommonDataKinds.Phone.getTypeLabel(res, type, ""))
.append(": ")
.append(phones.valueAt(i));
if (i + 1 < phones.size()) {
builder.append(", ");
}
}
}

if (emails != null) {
builder.append("\n\temails: ");
for (int i = 0; i < emails.size(); i++) {
int type = (int) emails.keyAt(i);
builder.append(ContactsContract.CommonDataKinds.Email.getTypeLabel(res, type, ""))
.append(": ")
.append(emails.valueAt(i));
if (i + 1 < emails.size()) {
builder.append(", ");
}
}
}
return builder.toString();
}

public void addEmail(int type, String address) {
if (emails == null) {
emails = new LongSparseArray<String>();
}
emails.put(type, address);
}

public void addPhone(int type, String number) {
if (phones == null) {
phones = new LongSparseArray<String>();
}
phones.put(type, number);
}
}

关于Android 获取所有联系人列表(姓名、电子邮件、电话)需要超过一分钟的时间来获取大约 700 个联系人,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26804387/

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