javascript - Angular 1.x，如何从回调中解决 parent 的 promise

Question

我正在尝试包装我的 post/get/put/delete 调用，以便在任何时候调用它们，如果它们失败，它们将检查过期的 token ，如果这是失败的原因，则重试，否则只需解决响应/错误。试图避免重复代码四次，但我不确定如何从非匿名回调中解决。

   factory.post = function (url, data, config) {
        var deferred = $q.defer();
        $http.post(url, data, config).then(factory.success, factory.fail);

        return deferred.promise;
     }

    factory.success = function (rsp) {
        if (rsp) {
           //how to resolve parent's promise from from here
        }
     }

另一种方法是将其复制 4 次:

.then(function (rsp) {
           factory.success(rsp, deferred);
        }, function (err) {
           factory.fail(err, deferred);
        });

Answer 1

一个解决方案可能是使用 bind功能。

function sum(a){
  return a + this.b;
}

function callFn(cb){
  return cb(1);
}

function wrapper(b){
  var extra = {b: b};
  return callFn(sum.bind(extra));
} 

console.log(wrapper(5));
console.log(wrapper(-5));
console.log(wrapper(50));

对于您的解决方案，请检查以下示例

factory.post = function (url, data, config) {
    var deferred = $q.defer();
    $http.post(url, data, config).then(factory.success.bind({deferred: deferred}), factory.fail.bind({deferred: deferred}));

    return deferred.promise;
 }

factory.success = function (rsp) {
    if (rsp) {
      this.deferred.resolve(rsp);
       //how to resolve parent's promise from from here
    }else {
      //retry or reject here
    }
 }