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android BluetoothDevice.getName() 返回 null

转载 作者:塔克拉玛干 更新时间:2023-11-01 21:22:04 24 4
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有时,BluetoothDevice.getName() 返回 null。我该如何解决?remoteDeviceName 在以下代码中可能为 null。我需要通过 remoteDeviceName 区分我的设备和其他设备。

BluetoothAdapter.getDefaultAdapter().startLeScan(new LeScanCallback() {
@Override
public void onLeScan(final BluetoothDevice device, final int rssi,
byte[] scanRecord) {
String remoteDeviceName = device.getName();
Log.d("Scanning", "scan device " + remoteDeviceName);
});

最佳答案

最后,我找到了解决方案:

1.对于连接的设备:

从gatt特性中读取设备名称org.bluetooth.characteristic.gap.device_name服务org.bluetooth.service.generic_access .

2.对于未连接的设备:

    /**
* Get device name from ble advertised data
*/
private LeScanCallback mScanCb = new LeScanCallback() {
@Override
public void onLeScan(final BluetoothDevice device, final int rssi,
byte[] scanRecord) {
final BleAdvertisedData badata = BleUtil.parseAdertisedData(scanRecord);
String deviceName = device.getName();
if( deviceName == null ){
deviceName = badata.getName();
}
}


////////////////////// Helper Classes: BleUtil and BleAdvertisedData ///////////////
final public class BleUtil {
private final static String TAG=BleUtil.class.getSimpleName();
public static BleAdvertisedData parseAdertisedData(byte[] advertisedData) {
List<UUID> uuids = new ArrayList<UUID>();
String name = null;
if( advertisedData == null ){
return new BleAdvertisedData(uuids, name);
}

ByteBuffer buffer = ByteBuffer.wrap(advertisedData).order(ByteOrder.LITTLE_ENDIAN);
while (buffer.remaining() > 2) {
byte length = buffer.get();
if (length == 0) break;

byte type = buffer.get();
switch (type) {
case 0x02: // Partial list of 16-bit UUIDs
case 0x03: // Complete list of 16-bit UUIDs
while (length >= 2) {
uuids.add(UUID.fromString(String.format(
"%08x-0000-1000-8000-00805f9b34fb", buffer.getShort())));
length -= 2;
}
break;
case 0x06: // Partial list of 128-bit UUIDs
case 0x07: // Complete list of 128-bit UUIDs
while (length >= 16) {
long lsb = buffer.getLong();
long msb = buffer.getLong();
uuids.add(new UUID(msb, lsb));
length -= 16;
}
break;
case 0x09:
byte[] nameBytes = new byte[length-1];
buffer.get(nameBytes);
try {
name = new String(nameBytes, "utf-8");
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
break;
default:
buffer.position(buffer.position() + length - 1);
break;
}
}
return new BleAdvertisedData(uuids, name);
}
}


public class BleAdvertisedData {
private List<UUID> mUuids;
private String mName;
public BleAdvertisedData(List<UUID> uuids, String name){
mUuids = uuids;
mName = name;
}

public List<UUID> getUuids(){
return mUuids;
}

public String getName(){
return mName;
}
}

关于android BluetoothDevice.getName() 返回 null,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26290640/

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