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Android HTTP GET登录方法

转载 作者:塔克拉玛干 更新时间:2023-11-01 19:11:00 24 4
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我有两个 Activity 。

主要 Activity 运行应用程序并初始化 http get 请求代码并将来自 JSON 的响应解析为字符串。

getmethod Activity 使用 http get 方法连接到服务器并将响应发送回我的主要 Activity 。

如何创建一个登录方法,让用户手动输入用户名和密码并将其传递给 get 方法?

最佳答案

您可以将此代码添加到您的主要 Activity - 它会为您完成所有繁重的工作。

/**
* Represents an asynchronous login/registration task used to authenticate
* the user.
*/
public class UserLoginTask extends AsyncTask<String, Void, Boolean> {

@Override
protected void onPostExecute(final Boolean success) {
if (success == true) {
//Do whatever your app does after login

} else {
//Let user know login has failed
}
}

@Override
protected Boolean doInBackground(String... login) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(
"YOUR_ADDRESS_HERE.COM");
String str = null;
String username = login[0];
String password = login[1];

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
nameValuePairs.add(new BasicNameValuePair("username", username));
nameValuePairs.add(new BasicNameValuePair("password", password));
try {
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
} catch (UnsupportedEncodingException e1) {
e1.printStackTrace();
return false;
}

try {
HttpResponse response = httpclient.execute(httppost);
str = EntityUtils.toString(response.getEntity());

} catch (IOException e) {
e.printStackTrace();
}

//Whatever parsing you need to do on the response
//This is an example if the webservice just passes back a String of "true or "false"

if (str.trim().equals("true")) {

return true;
} else {
return false;

}
}

您可以通过以下方式创建此对象:

  UserLoginTask mAuthTask = new UserLoginTask();

开始请求(也许从登录按钮放入 OnClick 事件?):

mAuthTask.execute(mUsername, mPassword);

关于Android HTTP GET登录方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13799486/

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