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C++11:如何检查类型是否是 "heterogeneous"非类型参数的给定类模板的实例化?

转载 作者:可可西里 更新时间:2023-11-01 18:37:05 25 4
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我知道检查类型是否是采用TYPE 参数的类模板的实例化是微不足道的,如此处解释:How can I check if a type is an instantiation of a given class template?

但是...是否有可能有一个可变参数“is_instantiation_of__ntp<...>”(NTP 代表非类型参数)接受具有任意数量的异构 非类型参数?例如:

template<char*, bool, long, size_t, char>
struct many_hetero_nontype_params_example {};

char HELLO_WORLD[] = "hello world";
using ManyHeteroNontypeParamsEx = many_hetero_nontype_params_example<HELLO_WORLD, false, -16, 777, 'x'>;

并能够按如下方式使用它:

is_instantiation_of__ntp<char*, bool, long, size_t, char, many_hetero_nontype_params_example, ManyHeteroNontypeParamsEx>::value

我知道这对于非类型参数列表可以很容易地实现,这些参数列表是 1) “同类”(相同类型的值),或 2) 很少的参数(这样一个非可变参数的解决方案是实用的)。我什至写了一个测试用例来演示这些特殊情况(用 gcc 4.7.0 编译)以更好地理解我在说什么:

namespace test__is_instantiation_of__
{
// is_instantiation_of
template< template<typename...> class Template, typename T >
struct is_instantiation_of : std::false_type {};
template< template<typename...> class Template, typename... Args >
struct is_instantiation_of< Template, Template<Args...> > : std::true_type {};

// is_instantiation_of__homogeneous_nontype_params__
template< typename NTP, template<NTP...> class Template, typename T >
struct is_instantiation_of__homogeneous_nontype_params__ : std::false_type {};
template< typename NTP, template<NTP...> class Template, NTP... Args >
struct is_instantiation_of__homogeneous_nontype_params__< NTP, Template, Template<Args...> > : std::true_type {};

// is_instantiation_of__fixedcount_nontype_params__
template< typename NTP1, typename NTP2, template<NTP1, NTP2> class Template, typename T >
struct is_instantiation_of__fixedcount_nontype_params__ : std::false_type {};
template< typename NTP1, typename NTP2, template<NTP1, NTP2> class Template, NTP1 v1, NTP2 v2 >
struct is_instantiation_of__fixedcount_nontype_params__< NTP1, NTP2, Template, Template<v1, v2> > : std::true_type {};

// type_params_example
template<typename T1, typename T2, typename T3>
struct type_params_example {};

// homogeneous_nontype_params_example
template<bool B1, bool B2, bool B3, bool B4>
struct homogeneous_nontype_params_example {};

// fixedcount_nontype_params_example
template<long L, char C>
struct fixedcount_nontype_params_example {};

using /*.........*/ TypeParamsEx = /*..........*/ type_params_example<std::string, std::tuple<long, void*>, double>;
using HomogenousNontypeParamsEx = homogeneous_nontype_params_example<true, false, true, false>;
using FixedCountNontypeParamsEx = fixedcount_nontype_params_example<777, 'x'>;

void run()
{
using std::cout;
using std::endl;

if ( is_instantiation_of<type_params_example, TypeParamsEx>::value ) {
cout << "[TypeParamsEx] specializes [type_params_example]" << endl;
}
if ( is_instantiation_of<type_params_example, HomogenousNontypeParamsEx>::value ) {
cout << "[HomogenousNontypeParamsEx] specializes [type_params_example]" << endl;
}
if ( is_instantiation_of<type_params_example, FixedCountNontypeParamsEx>::value ) {
cout << "[FixedCountNontypeParamsEx] specializes [type_params_example]" << endl;
}

if ( is_instantiation_of__homogeneous_nontype_params__<bool, homogeneous_nontype_params_example, TypeParamsEx>::value ) {
cout << "[TypeParamsEx] specializes [homogeneous_nontype_params_example]" << endl;
}
if ( is_instantiation_of__homogeneous_nontype_params__<bool, homogeneous_nontype_params_example, HomogenousNontypeParamsEx>::value ) {
cout << "[HomogenousNontypeParamsEx] specializes [homogeneous_nontype_params_example]" << endl;
}
if ( is_instantiation_of__homogeneous_nontype_params__<bool, homogeneous_nontype_params_example, FixedCountNontypeParamsEx>::value ) {
cout << "[FixedCountNontypeParamsEx] specializes [homogeneous_nontype_params_example]" << endl;
}

if ( is_instantiation_of__fixedcount_nontype_params__<long, char, fixedcount_nontype_params_example, TypeParamsEx>::value ) {
cout << "[TypeParamsEx] specializes [fixedcount_nontype_params_example]" << endl;
}
if ( is_instantiation_of__fixedcount_nontype_params__<long, char, fixedcount_nontype_params_example, HomogenousNontypeParamsEx>::value ) {
cout << "[HomogenousNontypeParamsEx] specializes [fixedcount_nontype_params_example]" << endl;
}
if ( is_instantiation_of__fixedcount_nontype_params__<long, char, fixedcount_nontype_params_example, FixedCountNontypeParamsEx>::value ) {
cout << "[FixedCountNontypeParamsEx] specializes [fixedcount_nontype_params_example]" << endl;
}
}
}

正如预期的那样,您得到的输出是:

[TypeParamsEx] specializes [type_params_example]
[HomeogenousNonTypeParamsEx] specializes [homogeneous_nontype_params_example]
[FixedCountNonTypeParamsEx] specializes [fixedcount_nontype_params_example]

问题是这些模板都不适用于 many_hetero_nontype_params_example(上图)。即:一个单一的可变参数“is_instantiation_of__ntp”,它将接受具有任意数量的异构非类型参数的模板。

我认为如果主模板不需要在模板参数列表的末尾有参数包,那么这将很容易实现。或者是否可以使用包装器结构/嵌套结构方法。这是我的(失败的)尝试:

namespace test__is_instantiation_of__nontypes__
{
template<char*, bool, long, size_t, char>
struct many_hetero_nontype_params_example {};

char HELLO_WORLD[] = "hello world";
using ManyHeteroNontypeParamsEx = many_hetero_nontype_params_example<HELLO_WORLD, false, -16, 777, 'x'>;

/*
* is_instantiation_of__nontypes_v1__ (version 1)
* if uncommented, syntax error as expected ...
* error: parameter pack 'NTPs' must be at the end of the template parameter list
* error: parameter pack argument 'NTPs ...' must be at the end of the template argument list
*/
//template< typename... NTPs, template<NTPs...> class Template, typename T >
//struct is_instantiation_of__nontypes_v1__ : std::true_type {};
//template< typename... NTPs, template<NTPs...> class Template, NTPs... NonTypeArgs >
//struct is_instantiation_of__nontypes_v1__< NTPs..., Template, Template<NonTypeArgs...> > : std::true_type {};

/*
* is_instantiation_of__nontypes_v2__ (version 2)
* no syntax error (but see instantiation errors below)
*/
template<typename... NTPs>
struct is_instantiation_of__nontypes_v2__
{
template< template<NTPs...> class Template, typename T >
struct impl : std::false_type {};

template< template<NTPs...> class Template, NTPs... NonTypeArgs >
struct impl< Template, Template<NonTypeArgs...> > : std::true_type {};
};

void run()
{
/*
* uncommented since "v1" template has syntax error, but this is how it would be used ...
*/
//if ( is_instantiation_of__nontypes_v1__<char*, bool, long, size_t, char, many_hetero_nontype_params_example, ManyHeteroNontypeParamsEx>::value ) {
// std::cout << "yes" << std::endl;
//}

/*
* "v2" template has no syntax error, but the following attempt to use it results in these errors ...
*
* error: type/value mismatch at argument 1 in template parameter list for 'template<class ... NTPs> template<template<template<NTPs ...<anonymous> > class Template, class T> template<class ... NTPs> template<NTPs ...<anonymous> > class Template, class T> struct is_instantiation_of__nontypes_v2__<NTPs>::impl'
* error: expected a template of type 'template<class ... NTPs> template<NTPs ...<anonymous> > class Template', got 'template<char* <anonymous>, bool <anonymous>, long int <anonymous>, long unsigned int <anonymous>, char <anonymous> > struct many_hetero_nontype_params_example'
*/
//if ( is_instantiation_of__nontypes_v2__<char*, bool, long, size_t, char>::impl<many_hetero_nontype_params_example, ManyHeteroNontypeParamsEx>::value ) {
// std::cout << "yes" << std::endl;
//}
}
}

...

是否有可能对此使用可变参数解决方案?

提前致谢。

最佳答案

您可能遇到了编译器错误。我试图将其简化为一个更简单的示例:

#include <iostream>

template<bool, char> struct A { };

template<typename... Ts>
struct test
{
template<typename T>
struct impl : std::false_type {};

template<Ts... Args>
struct impl<A<Args...>> : std::true_type {};
};

int main()
{
using IA = A<false, 'x'>;
std::cout << ((test<bool, char>::impl<IA>::value) ? "Y" : "N");
}

GCC 4.7.2 编译这个,但是编译的程序 prints the wrong output (N)。另一方面,Clang 3.2 做到了这一点,编译后的程序 prints the correct output (Y)。

这是对上述程序稍作修改的版本,其中 test类模板很像你的 is_instantiation_of__nontypes_v2__类模板:

#include <iostream>

template<bool, char> struct A {};

template<typename... Ts>
struct test
{
template<template<Ts...> class TT, typename T>
struct impl : std::false_type {};

template<template<Ts...> class TT, Ts... Args>
struct impl<TT, TT<Args...>> : std::true_type {};
};

int main()
{
using IA = A<false, 'x'>;
std::cout << ((test<bool, char>::impl<A, IA>::value) ? "Y" : "N");
}

当 Clang 编译它并且编译后的程序打印出正确的输出 ( Y ) 时,GCC 发出以下编译错误:

expected a template of type 'template<class ... Ts> template<Ts ...<anonymous> > class TT', got 'template<bool <anonymous>, char <anonymous> > struct A'.

看起来 GCC 不承认第一个模板模板参数应该有一个由 Ts 的扩展给出的模板参数列表。 .因此,在我看来这是 GCC 的一个错误。

关于C++11:如何检查类型是否是 "heterogeneous"非类型参数的给定类模板的实例化?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15175829/

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