C++ bool 函数返回 56

Question

我有一个返回 bool 值的函数:

bool restart()
{
    std::string answer;
    bool answered = false;
    while(answered == false)
    {
        cout << endl << endl << "Do you want to play again? y/n : ";
        cin >> answer;
        if(answer == "y" || answer == "Y" || answer == "1" || answer == "yes")
        {return true;}
        if(answer == "n" || answer == "N" || answer == "0" || answer == "no")
        {return false;}
    }
}

当我调用它时:

cout << restart();

我得到输出:

Do you want to play again? y/n : y
56

谁能看到如何解决这个奇怪的问题？提前致谢。

我现在的 WIP 代码:

#include <iostream>
#include <cstdlib>

using namespace std;

void drawScreen(int grid[3][3]);                               //
int movef(int grid[3][3], bool playersMove);
int updateGrid(int grid[3][3], int move, bool playersMove);
bool hasWon(int grid[3][3]);
bool swapMover(bool playersMove);                              //
bool restart();
void endGame();

int main()
{
    int grid[3][3] = {{1,2,3},{4,5,6},{7,8,9}};
    bool appRunning = true, gameRunning = true, playersMove = true;
    int move;

    // tests //
    std::cout << restart();
    // tests //

    //while(appRunning == true)
    //{
    //    while(gameRunning == true)
    //    {
    //        drawScreen(grid);
    //        move = movef(grid, playersMove);
    //        grid[3][3] = updateGrid(grid, move, playersMove);
    //        drawScreen(grid);
    //        gameRunning = hasWon(grid);
    //        playersMove = swapMover(playersMove);
    //    }
    //    appRunning = restart();
    //}
    //endGame();
    }

    void drawScreen(int grid[3][3])
    {
        for(int i = 0; i < 3; i++)
        {
             for(int j = 0; j < 3; j++)
             {
             if(grid[i][j] == 10){cout << "X  ";if(j == 2){cout << endl << endl;}}
             if(grid[i][j] == 11){cout << "O  ";if(j == 2){cout << endl << endl;}}
             if(grid[i][j] != 10 && grid[i][j] != 11){cout << grid[i][j] << "  ";
             if(j == 2){cout << endl << endl;}}
             }
        }
   }

  int movef(int grid[3][3], bool playersMove)
  {
       return 0;
  }

  int updateGrid(int grid[3][3], int move, bool playersMove)
  {
       return 0;
  }

  bool hasWon(int grid[3][3])
  {
      return false;
  }

  bool swapMover(bool playersMove)
  {
       if(playersMove == true){return false;}
       if(playersMove == false){return true;}
  }

bool restart()
{
    std::string answer;
    bool answered = false;
    while(answered == false)
    {
       cout << endl << endl << "Do you want to play again? y/n : ";
       cin >> answer;
       if(answer == "y" || answer == "Y" || answer == "1" || answer == "yes")
       {return true;}
        if(answer == "n" || answer == "N" || answer == "0" || answer == "no")
       {return false;}
    }
}

void endGame()
{

}

Answer 1

[这在某种程度上是我评论的转贴，因为 OP 说它解决了他的问题]

您没有在 while 循环外定义返回值。如果您以某种方式超出它，则不会返回值(尽管我不知道预期的行为是什么，甚至在这种情况下是否预期有任何行为)

为了让我的回答更彻底一点，我发现了这个: Why does flowing off the end of a non-void function without returning a value not produce a compiler error?