c++ - 出于一般原因抛出异常c++

Question

我的构造函数中有以下代码块(这只是一个示例，问题不是关于split，而是关于throwing a generic exception。另外, Boost 库无法使用。

Transfer::Transfer(const string &dest){
  try{
    struct stat st;
    char * token;
    std::string path(PATH_SEPARATOR) // if it is \ or / this macro will solve it
    token = strtok((char*)dest.c_str(), PATH_SEPARATOR) // 
    while(token != NULL){
        path += token;
        if(stat(path.c_str(), &st) != 0){
            if(mkdir(path.c_str()) != 0){
                 std:string msg("Error creating the directory\n");
                 throw exception // here is where this question lies
            }
        }

        token = strtok(NULL, PATH_SEPARATOR);
        path += PATH_SEPARATOR;

    }
  }catch(std::exception &e){
       //catch an exception which kills the program
       // the program shall not continue working.
  }

}

我想要的是在目录不存在且无法创建时抛出异常。我想抛出一个通用异常，我如何在 C++ 中做到这一点？PS:dest格式如下:

dest = /usr/var/temp/current/tree

Answer 1

请查看this answer .这解释了如何使用您自己的异常类

class myException: public std::runtime_error
{
    public:
        myException(std::string const& msg):
            std::runtime_error(msg)
        {}
};

void Transfer(){
  try{
          throw myException("Error creating the directory\n");
  }catch(std::exception &e){
      cout << "Exception " << e.what() << endl;
       //catch an exception which kills the program
       // the program shall not continue working.
  }

}

另外，如果你不想自己上课，你可以简单地通过

 throw std::runtime_error("Error creating the directory\n");