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c++ - "Manual"签名重载解析

转载 作者:可可西里 更新时间:2023-11-01 17:56:16 29 4
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我想做一个std::function像可以处理存储多个重载的对象。

语法有点像这样:my_function< int(double, int), double(double, double), char(int, int) > .

或者,更明确地说:

template<typename... Ts>
struct type_list {};

template<typename... Signatures >
struct my_function {
std::tuple< std::function<Signatures>... > m_functions;
typedef type_list< Signatures... > sig_list;
template<typename... Args>
typename pick_overload_signature< sig_list, type_list<Args...> >::return_value
operator()( Args&&... args )
{
return get<pick_overload_signature< sig_list, type_list<Args...> >::index>(m_functions)(std::forward<Args>(args)...);
}
};

我的问题:我应该怎么写pick_overload_signatures

这是我在上面所做的工作:

我的倾向是针对给定的一组参数编写函数签名的部分顺序,然后对函数签名的类型列表进行排序,然后获取最好的(可能在编译时断言最好的是独特的)。要做到这一点,我必须对函数签名有一个可靠的偏序(关于传入的一组参数)...

13.3.3.1 告诉我如何确定是否存在有效转换。我可以通过使用编译器为我进行转换来作弊,并使用 SFINAE 检测它是否发生在传入的给定参数和其中一个“重载”的签名上。

13.3.3.2 告诉我如何对这些转换进行排序。在这里,我必须检测转换序列是用户定义的还是标准序列。我不确定如何区分这两者。

也许我可以使用 traits 类来检测用户定义的转换序列的存在。检查 &S::operator D() 是否存在和 &D::D(S const&)&D::D(S)&D::D(S&&)或类似的东西。

has_user_defined_conversion<S,D>::value , has_standard_conversion<S,D>::value等等?

这种方法行得通吗?有人已经这样做了吗?或者有人已经完成了其中的一部分?

Result of Answers

#include <type_traits>
#include <cstddef>
#include <utility>
#include <functional>
#include <tuple>
#include <string>

// Packaged list of types:
template<typename... Ts>
struct type_list {
template<template<typename...>class target>
struct apply {
typedef target<Ts...> type;
};
template<typename T>
struct append {
typedef type_list< Ts..., T > type;
};
template<typename T>
struct prepend {
typedef type_list< T, Ts... > type;
};
};
template<template<typename>class mapper, typename list>
struct map_types {
typedef type_list<> type;
};
template<template<typename>class mapper, typename T0, typename... Ts>
struct map_types<mapper, type_list<T0, Ts...>> {
typedef typename map_types<mapper, type_list<Ts...>>::type tail;
typedef typename tail::template prepend< typename mapper<T0>::type >::type type;
};
template<template<typename>class mapper, typename list>
using MapTypes = typename map_types<mapper, list>::type;
template<template<typename>class temp>
struct apply_template_to {
template<typename T>
struct action {
typedef temp<T> type;
};
};
template<template<typename> class temp, typename list>
struct apply_to_each:map_types< apply_template_to<temp>::template action, list > {};
template<template<typename> class temp, typename list>
using ApplyToEach = typename apply_to_each<temp, list>::type;

template<std::size_t n, typename list>
struct nth_type {};
template<std::size_t n, typename first, typename... elements>
struct nth_type<n, type_list<first, elements...>>:nth_type<n-1, type_list<elements...>>
{};
template<typename first, typename... elements>
struct nth_type<0, type_list<first, elements...>>
{
typedef first type;
};
template<std::size_t n, typename list>
using NthType = typename nth_type<n, list>::type;

// func data
template<typename R, typename... Args>
struct unpacked_func {
typedef R result_type;
typedef type_list<Args...> args_type;
typedef unpacked_func< R, Args... > unpacked_type;
template<template<typename>class target>
struct apply {
typedef target<R(Args...)> type;
};
};

namespace unpack_details {
// Extracting basic function properties:
template<typename Func>
struct unpack_func {};
template<typename R, typename... Args>
struct unpack_func< R(Args...) > {
typedef unpacked_func< R, Args... > type;
};
template<typename R, typename... Args>
struct unpack_func< unpacked_func<R, Args...> >:
unpack_func< R(Args...) >
{};
}

template<typename Func>
using FuncUnpack = typename unpack_details::unpack_func<Func>::type;

template<typename Func>
struct func_props:func_props<FuncUnpack<Func>> {};
template<typename R, typename... Args>
struct func_props<unpacked_func<R, Args...>>:
unpacked_func<R, Args...>
{};

template<typename Func>
using FuncResult = typename func_props<Func>::result_type;
template<typename Func>
using FuncArgs = typename func_props<Func>::args_type;

template<typename Func>
struct make_func_ptr:make_func_ptr<FuncUnpack<Func>> {};

template<typename R, typename... Args>
struct make_func_ptr< unpacked_func< R, Args... > > {
typedef R(*type)(Args...);
};
template<typename Func>
using MakeFuncPtr = typename make_func_ptr<Func>::type;

// Marking a type up with an index:
template<typename R, std::size_t i>
struct indexed_type {
typedef R type;
enum { value = i };
};

// Sequences of size_t:
template<std::size_t... s>
struct seq {};
template<std::size_t min, std::size_t max, std::size_t... s>
struct make_seq: make_seq< min, max-1, max-1, s...> {};
template<std::size_t min, std::size_t... s>
struct make_seq< min, min, s...> {
typedef seq<s...> type;
};
template<std::size_t max, std::size_t min=0>
using MakeSeq = typename make_seq<max, min>::type;

namespace overload_details {
template<std::size_t n, typename... Overloads>
struct indexed_linear_signatures {};

template<typename Overload>
struct signature_generator {};
template<typename R, typename... Args>
struct signature_generator<unpacked_func<R, Args...>> {
R operator()(Args...); // no impl
};


template<typename Func, std::size_t i>
struct indexed_retval {};

template<typename R, typename... Args, std::size_t i>
struct indexed_retval< unpacked_func<R, Args...>, i > {
typedef unpacked_func<indexed_type<R,i>, Args...> type;
};

template<typename Func, std::size_t i>
using IndexRetval = typename indexed_retval<Func,i>::type;

void test1() {
typedef overload_details::IndexRetval< FuncUnpack<void()>, 0 > indexed;
indexed::apply<std::function>::type test = []()->indexed_type<void,0> {return indexed_type<void,0>();};
}

template<std::size_t n, typename Overload, typename... Overloads>
struct indexed_linear_signatures<n, Overload, Overloads...>:
signature_generator<IndexRetval<FuncUnpack<Overload>,n>>,
indexed_linear_signatures<n+1, Overloads...>
{};

template<typename T>
struct extract_index {};
template<typename T, std::size_t i>
struct extract_index<indexed_type<T,i>> {
enum {value = i};
};

template<typename T>
using Decay = typename std::decay<T>::type;

template<typename indexed_overloads, typename... Args>
struct get_overload_index {
enum{ value = extract_index< Decay<decltype( std::declval<indexed_overloads>()(std::declval<Args>()...) )> >::value };
};

template<typename Overloads, typename Args>
struct get_overload {};
template<typename... Overloads, typename... Args>
struct get_overload<type_list<Overloads...>, type_list<Args...>> {
typedef indexed_linear_signatures<0, Overloads...> sig_index;
enum { index = get_overload_index< sig_index, Args... >::value };
typedef FuncUnpack< NthType<index, type_list<Overloads...> > > unpacked_sig;
};

template<typename Overloads, typename Args>
using GetOverloadSig = typename get_overload< Overloads, Args >::unpacked_sig;
}

template<typename Overloads, typename Arguments>
struct pick_overload_signature {
enum{ index = overload_details::get_overload<Overloads, Arguments>::index };
typedef overload_details::GetOverloadSig<Overloads, Arguments> unpacked_sig;
};
#include <iostream>
void test1() {
typedef type_list< void(int), void(double) > overloads;
typedef type_list< int > args;
typedef pick_overload_signature< overloads, args > result;
std::cout << result::index << " should be 0\n";
typedef type_list< double > args2;
typedef pick_overload_signature< overloads, args2 > result2;
std::cout << result2::index << " should be 1\n";

// ;
typedef ApplyToEach< std::function, overloads >::apply< std::tuple >::type functions;
typedef std::tuple< std::function<void(int)>, std::function<void(double)> > functions0;
std::cout << std::is_same<functions, functions0>() << " should be true\n";

functions funcs{
[](int) { std::cout << "int!" << "\n"; },
[](double) { std::cout << "double!" << "\n"; }
};
std::get<result::index>(funcs)(0);
}

template< typename... Signatures >
struct my_function {
typedef type_list<Signatures...> signatures;
typedef std::tuple< std::function<Signatures>... > func_tuple;
func_tuple functions;
template<typename... Funcs>
explicit my_function(Funcs&&... funcs):
functions( std::forward<Funcs>(funcs)... )
{}

template<typename... Args>
auto
operator()(Args&&... args) const ->
typename overload_details::GetOverloadSig< signatures, type_list<Args...> >::result_type
{
return std::get<
pick_overload_signature< signatures, type_list<Args...> >::index
>(functions)(std::forward<Args>(args)...);
}
// copy/assign boilerplate
template<typename... OtherSignatures>
my_function( my_function<OtherSignatures...> const& o ):
functions( o.functions )
{}
template<typename... OtherSignatures>
my_function( my_function<OtherSignatures...> && o ):
functions( std::move(o.functions) )
{}
template<typename... OtherSignatures>
my_function& operator=( my_function<OtherSignatures...> const& o )
{
functions = o.functions;
return *this;
}
template<typename... OtherSignatures>
my_function& operator=( my_function<OtherSignatures...> && o ) {
functions = std::move(o.functions);
return *this;
}
};

struct printer {
template<typename T>
void operator()( T const& t ) {
std::cout << t << "\n";
}
};

void print(int x) {
std::cout << "int is " << x << "\n";
}
void print(std::string s) {
std::cout << "string is " << s << "\n";
}
void test2() {
my_function< void(int), void(std::string) > funcs{
[](int x){ std::cout << "int is " << x << "\n";},
[](std::string s){ std::cout << "string is " << s << "\n";}
};
std::cout << "test2\n";
funcs("hello");
funcs(0);
my_function< void(int), void(std::string) > funcs2{
printer(), printer()
};
funcs2("hello");
funcs2(12.7);
// doesn't work:
/*
my_function< void(int), void(std::string) > funcs3{
print,
print
};
*/
}
void test3() {

}
int main() {
test1();
test2();
test3();
}

尚未完成,但可用。

谢谢大家!

最佳答案

我确定它是可行的,但您可能会对这个感到满意 https://gist.github.com/dabrahams/3779345

template<class...Fs> struct overloaded;

template<class F1, class...Fs>
struct overloaded<F1, Fs...> : F1, overloaded<Fs...>::type
{
typedef overloaded type;

overloaded(F1 head, Fs...tail)
: F1(head),
overloaded<Fs...>::type(tail...)
{}
using F1::operator();
using overloaded<Fs...>::type::operator();
};

template<class F>
struct overloaded<F> : F
{
typedef F type;
using F::operator();
};

template<class...Fs>
typename overloaded<Fs...>::type overload(Fs...x)
{ return overloaded<Fs...>(x...); }

auto f = overload(
[](int x) { return x+1; },
[](char const* y) { return y + 1; },
[](int* y) { return y; });

关于c++ - "Manual"签名重载解析,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14972954/

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