perl - 如何在 Perl 中编写一个简单的 HTTP 代理？

Question

我不想使用 HTTP::Proxy 包，因为我想转储几个请求。我的一个类轮看起来像这样，但在尝试传递 header 时中断了:

perl -MData::Dumper -MHTTP::Daemon -MHTTP::Status -MLWP::UserAgent -e 'my $ua = LWP::UserAgent->new;my $d=new HTTP::Daemon(LocalPort=>1999);print "Please contact me at: <", $d->url, ">\n";while (my $c = $d->accept) {while (my $r = $c->get_request) {if ($r->method eq 'GET' and $r->url->path eq "/uploader") {$c->send_response("whatever.");print Dumper($r);}else{$response=$ua->request($r->method,"http://localhost:1996".$r->uri,$r->headers,$r->content);$c->send_response($response);}}}'

格式化，即:

#perl -e '
use Data::Dumper;
use HTTP::Daemon;
use HTTP::Status;
use LWP::UserAgent;
my $ua = LWP::UserAgent->new;
my $d=new HTTP::Daemon(LocalPort=>1999);
print "Please contact me at: < ", $d->url, " >\n";
while (my $c = $d->accept) {
  while (my $r = $c->get_request) {
    if ($r->method eq 'GET' and $r->url->path eq "/uploaded") {
      $c->send_response("whatever.");
      print Dumper($r);
    } else { 
      $response = $ua -> request(
        $r->method, 
        "http://localhost:1996" . $r->uri, 
        $r->headers, 
        $r->content);
      $c->send_response($response);
    }
  }
}#'

所以我不能只传递请求，因为我需要更改主机，而且我似乎不能只传递 header ...所以我应该怎么做才能保持简短。

那么谁能使它成为更好的单行代码？

Answer 1

天啊，我用这个修复了它:

#perl -e '
use Data::Dumper;
use HTTP::Daemon;
use HTTP::Status;
use LWP::UserAgent;
my $ua = LWP::UserAgent->new;
my $d=new HTTP::Daemon(LocalPort=>1999);
print "Please contact me at: < ", $d->url, " >\n";
while (my $c = $d->accept) {
  while (my $r = $c->get_request) {
    if ($r->method eq "GET" and $r->url->path eq "/uploaded") {
      $c->send_response("whatever.");
      print Dumper($r);
    } else { 
      $response = $ua -> request( HTTP::Request->new(
        $r->method, 
        "http://localhost:1996" . $r->uri, 
        $r->headers, 
        $r->content));
      $c->send_response($response);
    }
  }
}#'

请注意 HTTP::Request->new 是的...所以它可以工作，但有点慢。不过没关系