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c++ - 如何写一个简单的范围概念?

转载 作者:可可西里 更新时间:2023-11-01 16:47:22 28 4
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如何编写一个概念来描述启用基于范围的 for 循环的类型?

一种尝试是:

template < typename Range > concept bool RRange
= requires(Range range) {{std::begin(range),std::end(range)};};

但我真正想要的是这样的东西:

template < typename Range > concept bool RRange
= requires(Range range) {{for(auto&& item : range);};}; // compile error

RRange是表达式for(auto&& item : range);适用的所有类型的概念。实现这一目标的最佳方法是什么?

我正在使用带有 g++ -std=c++1z -fconcepts 的 GCC7 快照。

最佳答案

这是我在审查 [stmt.ranged] 时想到的。

#include <utility>
#include <experimental/type_traits>

template <class T> using begin_non_mf_t = decltype(begin(std::declval<T>()));
template <class T> using begin_mf_t = decltype(std::declval<T>().begin());
template <class T> using begin_t = decltype(T::begin);
template <class T> using end_non_mf_t = decltype(end(std::declval<T>()));
template <class T> using end_mf_t = decltype(std::declval<T>().end());
template <class T> using end_t = decltype(T::end);

template <class T>
constexpr bool has_member_begin_or_end {
std::experimental::is_detected_v<begin_mf_t,T> ||
std::experimental::is_detected_v<begin_t,T> ||
std::experimental::is_detected_v<end_mf_t,T> ||
std::experimental::is_detected_v<end_t,T>};

template <class T>
std::add_lvalue_reference_t<T> declref() noexcept;
template <class T> using declref_t = decltype(declref<T>());

template <class T>
concept bool Range =
requires /*Arrays*/ {
requires std::is_array_v<T>;
requires std::extent_v<T>!=0; // Extent is known.
} ||
/*Classes with member begin/end*/
requires {
requires std::is_class_v<T> && has_member_begin_or_end<T>;
} &&
requires (begin_mf_t<declref_t<T>> _begin,
end_mf_t<declref_t<T>> _end) {
{ _begin!=_end } -> bool;
{ *_begin } -> auto&&;
{ ++_begin };
} ||
/*Types with non-member begin/end*/
requires {
requires !std::is_class_v<T> || !has_member_begin_or_end<T>;
} &&
requires (begin_non_mf_t<declref_t<T>> _begin,
end_non_mf_t<declref_t<T>> _end) {
{ _begin!=_end } -> bool;
{ *_begin } -> auto&&;
{ ++_begin };
};

和测试用例。

#include <vector>

// Evaluates to true or diagnoses which constraints failed.
template <Range> constexpr bool is_range {true};

static_assert(!Range<void>);
static_assert(!Range<int>);
static_assert(!Range<int*>);
static_assert(!Range<int[]>);
static_assert(is_range<int[1]>);
static_assert(is_range<std::vector<int>>);

struct A { };
struct B {
int begin;
};
struct C {
int* begin();
int* end();
};
struct D { };
struct E {
int end;
};
enum F { };
struct G {
int* begin() &&;
int* end();
};
struct H {
int* begin() &&;
int* end() &&;
};
int* begin(D);
int* end(D);
int* begin(E);
int* end(E);
int* begin(F);
int* end(F);
int* begin(H);
int* end(H);

static_assert(!Range<A>);
static_assert(!Range<B>);
static_assert(is_range<C>);
static_assert(is_range<D>);
static_assert(!Range<E>);
static_assert(is_range<F>);
static_assert(!Range<G>);
static_assert(!Range<H>);

int main() { }

关于c++ - 如何写一个简单的范围概念?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40676743/

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