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c++ - 尝试转换 str 字符串以用于 std::getline 定界符

转载 作者:可可西里 更新时间:2023-11-01 16:39:40 29 4
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我正在尝试获取 std::string 值并将其用作 std::getline() 函数中的分隔符但无论我做什么,编译器都会给我错误。这就是我想要做的:

std::stringstream ss(s);
std::string item;
std::string delim ="&&=";
int ssize = delim.size();
int newssize = ssize+1;
char del[SSIZE]; // also here when i try gives error
strcpy(del,delim.c_str());

char * delrr[1024] = delim.c_str(); //gives error

while(std::getline(ss,item,delrr)) {
elems.push_back(item);
}

我得到的错误总是关于 const char* 转换。

 error C2440: 'initializing' : cannot convert from 'const char *' to 'char *[1024]'
1> There are no conversions to array types, although there are conversions to references or pointers to arrays
1>.\UT.cpp(179) : error C2780: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &)' : expects 2 arguments - 3 provided
1> d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(527) : see declaration of 'std::getline'
1>.\UT.cpp(179) : error C2784: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &,const _Elem)' : could not deduce template argument for 'std::basic_istream<_Elem,_Traits> &' from 'std::stringstream'
1> d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(475) : see declaration of 'std::getline'
1>.\UT.cpp(179) : error C2784: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &,const _Elem)' : could not deduce template argument for 'std::basic_istream<_Elem,_Traits> &' from 'std::stringstream'
1> d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(475) : see declaration of 'std::getline'
1>.\UT.cpp(179) : error C2782: 'std::basic_istream<_Elem,_Traits> &std::getline(std::basic_istream<_Elem,_Traits> &,std::basic_string<_Elem,_Traits,_Alloc> &,const _Elem)' : template parameter '_Elem' is ambiguous
1> d:\Program Files\Microsoft Visual Studio 9.0\VC\include\string(475) : see declaration of 'std::getline'
1> could be 'char **'
1> or 'char'

更新:
找到答案: How do I tokenize a string in C++?
http://www.codeproject.com/Articles/23198/C-String-Toolkit-StrTk-Tokenizer

最佳答案

getline() 的第三个参数是一个字符,而不是一个字符数组。参见 this .如果您需要多个分隔符或由多个字符组成的分隔符,则不能使用此功能。

使用 find() 和 substr()。

关于c++ - 尝试转换 str 字符串以用于 std::getline 定界符,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9215052/

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