gpt4 book ai didi

c - 发送原始 http header

转载 作者:可可西里 更新时间:2023-11-01 16:27:16 26 4
gpt4 key购买 nike

我有以下原始 HTTP 请求:

GET http://www.google.ie/ HTTP/1.1
Host: www.google.ie
User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:5.0) Gecko/20100101 Firefox/5.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-us,en;q=0.5
Accept-Encod...

我试图从我的本地主机发送这个。有人可以指出正确的方向,告诉我如何用 C 或 C++ 执行此操作吗?

我目前正在查看套接字,但它并没有真正起作用。

   int sockfdi, portnoi, ni;
struct sockaddr_in serv_addri;
struct hostent *serveri;
portnoi =80;

sockfdi = socket(AF_INET, SOCK_STREAM, 0);
if (sockfdi < 0){
error("***ERROR opening socket");
}
serveri = gethostbyname("172.16.1.218");
if (serveri == NULL){
fprintf(stderr,"***ERROR, no such host\n");
exit(0);
}

bzero((char *) &serv_addri, sizeof(serv_addri));
serv_addri.sin_family = AF_INET;
bcopy((char *)serveri->h_addr, (char *)&serv_addri.sin_addr.s_addr, serveri->h_length);
serv_addri.sin_port = htons(portnoi);
if (connect(sockfdi,(struct sockaddr *) &serv_addri,sizeof(serv_addri)) < 0){
error("***ERROR connecting");
}
printf("Please enter the message: ");
bzero(buffer,256);

最佳答案

您可以尝试使用 libcurl而不是套接字:

#include <stdio.h>
#include <curl/curl.h>

int main(void)
{
CURL *curl;
CURLcode res;
struct curl_slist *headers = NULL;

curl = curl_easy_init();
if(curl) {
headers = curl_slist_append(headers, "Host: www.google.ie");
headers = curl_slist_append(headers, "User-Agent: Mozilla/5.0 (X11; Linux x86_64; rv:5.0) Gecko/20100101 Firefox/5.0");
headers = curl_slist_append(headers, "Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8");
headers = curl_slist_append(headers, "Accept-Language: en-us,en;q=0.5");
/* Add more headers here */
curl_easy_setopt(curl, CURLOPT_URL, "http://www.google.ie/");
curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
res = curl_easy_perform(curl);

/* always cleanup */
curl_slist_free_all(headers);
curl_easy_cleanup(curl);
}
return 0;
}

关于c - 发送原始 http header ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7065757/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com