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C++决策树实现问题: Think In Code

转载 作者:可可西里 更新时间:2023-11-01 16:21:58 26 4
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我已经编码了几年,但我仍然没有掌握伪编码的窍门,也没有真正用代码思考问题。由于这个问题,我无法弄清楚在创建学习决策树时究竟要做什么。

这是我看过的一些网站相信我还有很多

Decision Tree Tutorials

DMS Tutorials

还有几本书,例如 Ian Millington 的 AI for Games,其中包括对决策树中使用的不同学习算法的详细介绍,以及基本上都是关于决策树和理论的游戏编程行为数学。我了解决策树的概念以及熵、ID3 和一些关于如何交织遗传算法并让决策树决定 GA 节点的知识。他们提供了很好的洞察力,但不是我真正想要的。

我确实有一些为决策树创建节点的基本代码,我相信我知道如何实现实际逻辑,但如果我对程序没有目的或者没有熵或学习算法,那它就没有用涉及。

我想问的是,有人可以帮我弄清楚我需要做什么来创建这个学习决策树。我的节点在它们自己的类中,它们通过函数来​​创建树,但是我如何将熵放入其中,它是否应该有一个类,一个结构,我不确定如何将它组合在一起。伪代码和我将使用所有这些理论和数字去向何处的想法。只要我知道我需要编码什么,我就可以把代码放在一起。任何指导将不胜感激。

基本上,我将如何处理这个问题。

添加学习算法,例如 ID3 和 Entropy。应该如何设置?

一旦我确实弄清楚了如何处理这一切,我计划将其实现到一个状态机中,该状态机以游戏/模拟格式经历不同的状态。所有这些都已经设置好了,我只是认为它可以是独立的,一旦我弄明白了,我就可以将它移到另一个项目中。

这是我目前拥有的源代码。

提前致谢!

Main.cpp:

int main()
{
//create the new decision tree object
DecisionTree* NewTree = new DecisionTree();

//add root node the very first 'Question' or decision to be made
//is monster health greater than player health?
NewTree->CreateRootNode(1);

//add nodes depending on decisions
//2nd decision to be made
//is monster strength greater than player strength?
NewTree->AddNode1(1, 2);

//3rd decision
//is the monster closer than home base?
NewTree->AddNode2(1, 3);

//depending on the weights of all three decisions, will return certain node result
//results!
//Run, Attack,
NewTree->AddNode1(2, 4);
NewTree->AddNode2(2, 5);
NewTree->AddNode1(3, 6);
NewTree->AddNode2(3, 7);

//Others: Run to Base ++ Strength, Surrender Monster/Player,
//needs to be made recursive, that way when strength++ it affects decisions second time around DT

//display information after creating all the nodes
//display the entire tree, i want to make it look like the actual diagram!
NewTree->Output();

//ask/answer question decision making process
NewTree->Query();

cout << "Decision Made. Press Any Key To Quit." << endl;

//pause quit, oh wait how did you do that again...look it up and put here

//release memory!
delete NewTree;

//return random value
//return 1;
}

决策树.h:

//the decision tree class
class DecisionTree
{
public:
//functions
void RemoveNode(TreeNodes* node);
void DisplayTree(TreeNodes* CurrentNode);
void Output();
void Query();
void QueryTree(TreeNodes* rootNode);
void AddNode1(int ExistingNodeID, int NewNodeID);
void AddNode2(int ExistingNodeID, int NewNodeID);
void CreateRootNode(int NodeID);
void MakeDecision(TreeNodes* node);

bool SearchAddNode1(TreeNodes* CurrentNode, int ExistingNodeID, int NewNodeID);
bool SearchAddNode2(TreeNodes* CurrentNode, int ExistingNodeID, int NewNodeID);

TreeNodes* m_RootNode;

DecisionTree();

virtual ~DecisionTree();
};

Decisions.cpp:

int random(int upperLimit);

//for random variables that will effect decisions/node values/weights
int random(int upperLimit)
{
int randNum = rand() % upperLimit;
return randNum;
}

//constructor
//Step 1!
DecisionTree::DecisionTree()
{
//set root node to null on tree creation
//beginning of tree creation
m_RootNode = NULL;
}

//destructor
//Final Step in a sense
DecisionTree::~DecisionTree()
{
RemoveNode(m_RootNode);
}

//Step 2!
void DecisionTree::CreateRootNode(int NodeID)
{
//create root node with specific ID
// In MO, you may want to use thestatic creation of IDs like with entities. depends on how many nodes you plan to have
//or have instantaneously created nodes/changing nodes
m_RootNode = new TreeNodes(NodeID);
}

//Step 5.1!~
void DecisionTree::AddNode1(int ExistingNodeID, int NewNodeID)
{
//check to make sure you have a root node. can't add another node without a root node
if(m_RootNode == NULL)
{
cout << "ERROR - No Root Node";
return;
}

if(SearchAddNode1(m_RootNode, ExistingNodeID, NewNodeID))
{
cout << "Added Node Type1 With ID " << NewNodeID << " onto Branch Level " << ExistingNodeID << endl;
}
else
{
//check
cout << "Node: " << ExistingNodeID << " Not Found.";
}
}

//Step 6.1!~ search and add new node to current node
bool DecisionTree::SearchAddNode1(TreeNodes *CurrentNode, int ExistingNodeID, int NewNodeID)
{
//if there is a node
if(CurrentNode->m_NodeID == ExistingNodeID)
{
//create the node
if(CurrentNode->NewBranch1 == NULL)
{
CurrentNode->NewBranch1 = new TreeNodes(NewNodeID);
}
else
{
CurrentNode->NewBranch1 = new TreeNodes(NewNodeID);
}
return true;
}
else
{
//try branch if it exists
//for a third, add another one of these too!
if(CurrentNode->NewBranch1 != NULL)
{
if(SearchAddNode1(CurrentNode->NewBranch1, ExistingNodeID, NewNodeID))
{
return true;
}
else
{
//try second branch if it exists
if(CurrentNode->NewBranch2 != NULL)
{
return(SearchAddNode2(CurrentNode->NewBranch2, ExistingNodeID, NewNodeID));
}
else
{
return false;
}
}
}
return false;
}
}

//Step 5.2!~ does same thing as node 1. if you wanted to have more decisions,
//create a node 3 which would be the same as this maybe with small differences
void DecisionTree::AddNode2(int ExistingNodeID, int NewNodeID)
{
if(m_RootNode == NULL)
{
cout << "ERROR - No Root Node";
}

if(SearchAddNode2(m_RootNode, ExistingNodeID, NewNodeID))
{
cout << "Added Node Type2 With ID " << NewNodeID << " onto Branch Level " << ExistingNodeID << endl;
}
else
{
cout << "Node: " << ExistingNodeID << " Not Found.";
}
}

//Step 6.2!~ search and add new node to current node
//as stated earlier, make one for 3rd node if there was meant to be one
bool DecisionTree::SearchAddNode2(TreeNodes *CurrentNode, int ExistingNodeID, int NewNodeID)
{
if(CurrentNode->m_NodeID == ExistingNodeID)
{
//create the node
if(CurrentNode->NewBranch2 == NULL)
{
CurrentNode->NewBranch2 = new TreeNodes(NewNodeID);
}
else
{
CurrentNode->NewBranch2 = new TreeNodes(NewNodeID);
}
return true;
}
else
{
//try branch if it exists
if(CurrentNode->NewBranch1 != NULL)
{
if(SearchAddNode2(CurrentNode->NewBranch1, ExistingNodeID, NewNodeID))
{
return true;
}
else
{
//try second branch if it exists
if(CurrentNode->NewBranch2 != NULL)
{
return(SearchAddNode2(CurrentNode->NewBranch2, ExistingNodeID, NewNodeID));
}
else
{
return false;
}
}
}
return false;
}
}

//Step 11
void DecisionTree::QueryTree(TreeNodes* CurrentNode)
{
if(CurrentNode->NewBranch1 == NULL)
{
//if both branches are null, tree is at a decision outcome state
if(CurrentNode->NewBranch2 == NULL)
{
//output decision 'question'
///////////////////////////////////////////////////////////////////////////////////////
}
else
{
cout << "Missing Branch 1";
}
return;
}
if(CurrentNode->NewBranch2 == NULL)
{
cout << "Missing Branch 2";
return;
}

//otherwise test decisions at current node
MakeDecision(CurrentNode);
}

//Step 10
void DecisionTree::Query()
{
QueryTree(m_RootNode);
}

////////////////////////////////////////////////////////////
//debate decisions create new function for decision logic

// cout << node->stringforquestion;

//Step 12
void DecisionTree::MakeDecision(TreeNodes *node)
{
//should I declare variables here or inside of decisions.h
int PHealth;
int MHealth;
int PStrength;
int MStrength;
int DistanceFBase;
int DistanceFMonster;

////sets random!
srand(time(NULL));

//randomly create the numbers for health, strength and distance for each variable
PHealth = random(60);
MHealth = random(60);
PStrength = random(50);
MStrength = random(50);
DistanceFBase = random(75);
DistanceFMonster = random(75);

//the decision to be made string example: Player health: Monster Health: player health is lower/higher
cout << "Player Health: " << PHealth << endl;
cout << "Monster Health: " << MHealth << endl;
cout << "Player Strength: " << PStrength << endl;
cout << "Monster Strength: " << MStrength << endl;
cout << "Distance Player is From Base: " << DistanceFBase << endl;
cout << "Disntace Player is From Monster: " << DistanceFMonster << endl;

//MH > PH
//MH < PH
//PS > MS
//PS > MS
//DB > DM
//DB < DM

//good place to break off into different decision nodes, not just 'binary'

//if statement lower/higher query respective branch
if(PHealth > MHealth)
{
}
else
{
}
//re-do question for next branch. Player strength: Monster strength: Player strength is lower/higher
//if statement lower/higher query respective branch
if(PStrength > MStrength)
{
}
else
{
}

//recursive question for next branch. Player distance from base/monster.
if(DistanceFBase > DistanceFMonster)
{
}
else
{
}
//DECISION WOULD BE MADE
//if statement?
// inside query output decision?
//cout << <<

//QueryTree(node->NewBranch2);

//MakeDecision(node);
}

//Step.....8ish?
void DecisionTree::Output()
{
//take repsective node
DisplayTree(m_RootNode);
}

//Step 9
void DecisionTree::DisplayTree(TreeNodes* CurrentNode)
{
//if it doesn't exist, don't display of course
if(CurrentNode == NULL)
{
return;
}

//////////////////////////////////////////////////////////////////////////////////////////////////
//need to make a string to display for each branch
cout << "Node ID " << CurrentNode->m_NodeID << "Decision Display: " << endl;

//go down branch 1
DisplayTree(CurrentNode->NewBranch1);

//go down branch 2
DisplayTree(CurrentNode->NewBranch2);
}

//Final step at least in this case. A way to Delete node from tree. Can't think of a way to use it yet but i know it's needed
void DecisionTree::RemoveNode(TreeNodes *node)
{
//could probably even make it to where you delete a specific node by using it's ID
if(node != NULL)
{
if(node->NewBranch1 != NULL)
{
RemoveNode(node->NewBranch1);
}

if(node->NewBranch2 != NULL)
{
RemoveNode(node->NewBranch2);
}

cout << "Deleting Node" << node->m_NodeID << endl;

//delete node from memory
delete node;
//reset node
node = NULL;
}
}

TreeNodes.h:

using namespace std;
//tree node class
class TreeNodes
{
public:
//tree node functions
TreeNodes(int nodeID/*, string QA*/);
TreeNodes();

virtual ~TreeNodes();

int m_NodeID;

TreeNodes* NewBranch1;
TreeNodes* NewBranch2;
};

TreeNodes.cpp:

//contrctor
TreeNodes::TreeNodes()
{
NewBranch1 = NULL;
NewBranch2 = NULL;

m_NodeID = 0;
}

//deconstructor
TreeNodes::~TreeNodes()
{ }

//Step 3! Also step 7 hah!
TreeNodes::TreeNodes(int nodeID/*, string NQA*/)
{
//create tree node with a specific node ID
m_NodeID = nodeID;

//reset nodes/make sure! that they are null. I wont have any funny business #s -_-
NewBranch1 = NULL;
NewBranch2 = NULL;
}

最佳答案

如果我错了请纠正我,但从 http://dms.irb.hr/tutorial/tut_dtrees.php 的图片来看和 http://www.decisiontrees.net/?q=node/21实际的决策逻辑应该放在节点中,而不是树中。您可以通过使用多态节点对其进行建模,每个节点对应一个决策。对树结构进行一些更改并对决策委托(delegate)进行少量修改,您的代码应该没问题。

关于C++决策树实现问题: Think In Code,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5646120/

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