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java - HTTP 请求对象

转载 作者:可可西里 更新时间:2023-11-01 16:05:57 25 4
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标准 Java SE 中是否有一个对象可以接受来自套接字的 HTTP 请求?我找到了如何创建和发送一个,但是我还没有找到从套接字检索 HTTP 对象的方法。我可以自己创建一个,但我宁愿依赖经过严格测试的对象。

鉴于 JSP 的结构,这似乎很容易获得。

最佳答案

Java 6 SDK 中有一个小型 HTTP 服务器(不确定它是在 JRE 中还是在非 Sun JVM 中)。

来自 http://www.java2s.com/Code/Java/JDK-6/LightweightHTTPServer.htm :

import java.io.IOException;
import java.io.OutputStream;
import java.net.InetSocketAddress;
import java.util.Iterator;
import java.util.List;
import java.util.Set;
import java.util.concurrent.Executors;

import com.sun.net.httpserver.Headers;
import com.sun.net.httpserver.HttpExchange;
import com.sun.net.httpserver.HttpHandler;
import com.sun.net.httpserver.HttpServer;

public class HttpServerDemo {
public static void main(String[] args) throws IOException {
InetSocketAddress addr = new InetSocketAddress(8080);
HttpServer server = HttpServer.create(addr, 0);

server.createContext("/", new MyHandler());
server.setExecutor(Executors.newCachedThreadPool());
server.start();
System.out.println("Server is listening on port 8080" );
}
}

class MyHandler implements HttpHandler {
public void handle(HttpExchange exchange) throws IOException {
String requestMethod = exchange.getRequestMethod();
if (requestMethod.equalsIgnoreCase("GET")) {
Headers responseHeaders = exchange.getResponseHeaders();
responseHeaders.set("Content-Type", "text/plain");
exchange.sendResponseHeaders(200, 0);

OutputStream responseBody = exchange.getResponseBody();
Headers requestHeaders = exchange.getRequestHeaders();
Set<String> keySet = requestHeaders.keySet();
Iterator<String> iter = keySet.iterator();
while (iter.hasNext()) {
String key = iter.next();
List values = requestHeaders.get(key);
String s = key + " = " + values.toString() + "\n";
responseBody.write(s.getBytes());
}
responseBody.close();
}
}
}

关于java - HTTP 请求对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1695978/

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